3 years ago

A regular octagon with sides of length 7 and an apothem of length 10.49 has an area of how many square units

Mathematics

1 answer:

Ray Of Light [21]3 years ago

6 0

Answer:

The area of the regular octagon is $293.72\ units^{2}$

Step-by-step explanation:

we know that

The area of the regular polygon is equal to

$A=\frac{1}{2}Pa$

where

P is the perimeter of the regular polygon

a is the apothem

<em>Find the perimeter P</em>

$P=8(7)=56\ units$

Find the area

$A=\frac{1}{2}(56)(10.49)=293.72\ units^{2}$

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Simplify 7 log3 k + 6 log3 m − 9 log3 n

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The answer is log3 k to the seventh power m to the sixth power over n to the ninth power

a * logₓ(y) = logₓ(yᵃ)
7 log₃ (k) = log₃ (k⁷)
6 log₃ (m) = log₃ (m⁶)
9 log₃ (n) = log₃ (n⁹)

7 log₃ (k) + 6 log₃ (m) - 9 log₃ (n) = log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹)

logₓ(y) + logₓ(z) = logₓ(y * z)
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logₓ(y) - logₓ(z) = logₓ(y / z)
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3 years ago

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Nataly_w [17]

Answer:

The correct line plot is choice C.

Step-by-step explanation:

If you look at the data values, you'll notice that there are three $11\frac{1}{4}$ , and the only line plot that depicts this is choice C, so that is the correct answer.