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nikitadnepr [17]
3 years ago
6

Luke picks up a triangular prism and examines it. What is the volume of the triangular prism in cubic cm

Mathematics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

4608

Step-by-step explanation:

(12*16)/2

then multiply by  48

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Triangle GHJ is rotated 90° about point X, resulting in
Bumek [7]

the correct answer is your third choice.

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2 years ago
The teacher asks Mel and Kate to use base 10 blocks to model the number that is ten times the value of 4 rods. Mel's modle uses
AveGali [126]
Kate's model is correct because 10 times the value of 4 rods, 10(4(10)), is 400. Mel's model represents 4(1)=4, which is incorrect. Kate's model represents 4*100=400, which is correct.
Hope I answered your question!
4 0
2 years ago
PLEASE ANSWER + BRAINLIEST!!<br><br> Factor completely.<br><br> 4k - 20k^9 =<br><br> 3b^2 - 108 =
Neporo4naja [7]
4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)

3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)

Used:\ (a-b)(a+b)=a^2-b^2
7 0
3 years ago
Find two additional roots of P(x)=0.<br><br> 13+sqrt 3 and 7i
vova2212 [387]
So, x = 13, x = √3 and x =7i.

now, recall that for an EVEN radical, there are two possible roots, namely is say √3 is say hmmm some value "a", that means that a*a = √3, however, -a*-a is also √3, therefore, ±√3 are two valid values, and therefore -√3 is another one.

now.... keep in mind that, complex solutions or roots, never come all by their lonesome, their sister is always with them, the conjugate, so, for 7i or namely 0 + 7i, her sister is always around, 0 - 7i, which is the other root.
4 0
3 years ago
Rectangle w/area of 91 has dimensions of (x+2) and (2x+3). Solve for dimensions.
Leviafan [203]

Answer:

5unit

Step-by-step explanation: since area of rectangle = length*width

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On further solving

2x^2+75x-85=0

2x^2-10x+17x-85=0

2x(x-5)+17(x-5)=0

(2x+17)(x-5)=0

x=5unit

8 0
2 years ago
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