Question

How do i solve -3x-(-2)=(-10)

Answer 1

Step-by-step explanation:

$-3x - (-2) = (-10)$

First, let's remove the parentheses and distribute any minus signs that are present outside of the parentheses:

$-3x + 2 = -10$

Next, let's subtract $2$ from both sides to isolate the terms with an $x$ on the left-hand side of the equation:

$-3x + 2 - 2 = -10 - 2$

$-3x = -12$

Finally, let's divide both sides by $-3$ to get the $x$ by itself on the left-hand side of the equation:

$\frac{-3x}{-3} = \frac{-12}{-3}$

$x = 4$

Answer 2

Answer:

x = 4

Step-by-step explanation:

-3x -(-2) = (-10)

First open the bracket

-3x + 2 = -10

Next is to subtract 2 from both-side of the equation

-3x + 2 - 2 = -10 - 2

-3x = -12

Then divide both-side of the equation by -3 to get the value of x

$\frac{-3x}{-3}$ = $\frac{-12}{-3}$

(On the left-hand side of the equation -3 at the numerator will cancel out -3 at the denominator while on the right-hand side of the equation -12 will be divided by -3)

x = $\frac{-12}{-3}$

x = 4