Via synthetic division, we have
-3 | 1 8 19 12
... | -3 -15 -12
= = = = = = = = = = = =
... | 1 5 4 0
which is to say,
![\dfrac{b^3+8b^2+19b+12}{b+3}=b^2+5b+4](https://tex.z-dn.net/?f=%5Cdfrac%7Bb%5E3%2B8b%5E2%2B19b%2B12%7D%7Bb%2B3%7D%3Db%5E2%2B5b%2B4)
is the area of the base.
Answer:
Point (1,8)
Step-by-step explanation:
We will use segment formula to find the coordinates of point that will partition our line segment PQ in a ratio 3:1.
When a point divides any segment internally in the ratio m:n, the formula is:
![[x=\frac{mx_2+nx_1}{m+n},y= \frac{my_2+ny_1}{m+n}]](https://tex.z-dn.net/?f=%5Bx%3D%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2Cy%3D%20%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5D)
Let us substitute coordinates of point P and Q as:
,
![y_1=-4](https://tex.z-dn.net/?f=y_1%3D-4)
![x_2=4](https://tex.z-dn.net/?f=x_2%3D4)
![y_2=12](https://tex.z-dn.net/?f=y_2%3D12)
![m=3](https://tex.z-dn.net/?f=m%3D3)
![[x=\frac{4}{4},y=\frac{32}{4}]](https://tex.z-dn.net/?f=%5Bx%3D%5Cfrac%7B4%7D%7B4%7D%2Cy%3D%5Cfrac%7B32%7D%7B4%7D%5D)
Therefore, point (1,8) will partition the directed line segment PQ in a ratio 3:1.
Answer:
x=30
Step-by-step explanation:
Find the value of x that will make A and B parallel
For A & B to be parallel, the interior angles must be supplementary, i.e.
4x+2x = 180
6x=180
x=30
When x=30, the interior angles are 120 and 60 which are supplementary.
The ANWSER is B hope this helps
Subtract the first part in parentheses and then when u get the answer then subtract the next part