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2 years ago

I need the answer. !’

Mathematics

1 answer:

EleoNora [17]2 years ago

3 0

Answer:

B) -9

Step-by-step explanation:

31+2= 33 --> -33 + 49= --> 16

-5x-5= 25

16 -25 = -9

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Which graph best represents a kitten's weight for the first two years after birth if, from birth to 2 years old, its weight incr

elena-14-01-66 [18.8K]

Answer:

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Step-by-step explanation:

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3 years ago

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A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners

Vlada [557]

Answer:

The measures of the angles at its corners are $59.1\°,35.4\°,85.5\°$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

$185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)$

$2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}$

$cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))$ $cos(A)=0.513953$

$A=arccos(0.513953)=59.1\°$

step 2

Find the measure of angle B

Applying the law of cosines

$125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)$

$2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}$

$cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))$ $cos(B)=0.81489$

$B=arccos(0.81489)=35.4\°$

step 3

Find the measure of angle C

Applying the law of cosines

$215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)$

$2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}$

$cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))$ $cos(C)=0.0784$

$C=arccos(0.0784)=85.5\°$

3 0

2 years ago

Sin(theta)+cos(theta)=0 what is theta? 20 points someone please help (A-Level pure maths)

Bumek [7]

Answer:

sin(theta) + cos(theta) = 0

sin(theta) = -cos(theta)

sin(theta)/cos(theta) = -1

tan(theta) = -1

theta = - 45° ± k·180°

8 0

3 years ago

HELP PLEASE HELP HELP

kupik [55]

I think it’s 0but not s

5 0

2 years ago

What are the solutions of x² + 6x - 16 = 0?

AveGali [126]

Step-by-step explanation:

$x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}}{2\cdot \:1}\\\sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}\\\sqrt{6^2+64}\\\sqrt{36+64}\\\sqrt{100}\\\sqrt{10^2}\\=10\\x_1=\frac{-6+10}{2\cdot \:1},\:x_2=\frac{-6-10}{2\cdot \:1}\\\\\bold{x_1:2}\\\frac{-6+10}{2\cdot \:1}\\\frac{4}{2\cdot \:1}\\\frac{4}{2}\\=2\\\\\bold{x_2:-8}\\\frac{-6-10}{2\cdot \:1}\\\frac{-16}{2\cdot \:1}\\\frac{-16}{2}\\-\frac{16}{2}\\=-8$

Answer:

x₁ = 2

x₂ = -8

6 0

5 months ago