Plz help me get the answer to these

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

8 0

Remove the brackets

-5a + 9b + 7a combine -5a and 7a

7a - 5a + 9b

2a + 9b Answer

Don't go any further. There is nothing else to do. These are unlike terms and cannot be reduced or combined.

Colt1911 [192]3 years ago

4 0

Step-by-step explanation:

$(-5a+9b)+7a\qquad\text{combine like terms}\\\\=(-5a+7a)+9b\\\\=2a+9b$

You might be interested in

What is the center of the ellipse x2+5y2–45=0?

jeka94

Answer:

Center is at (0,0)

Step-by-step explanation:

An equation of ellipse in standard form is:

$\displaystyle{\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2} = 1$

Where center is at point (h,k)

From the equation of $\displaystyle{x^2+5y^2-45=0}$ . First, we add 45 both sides:

$\displaystyle{x^2+5y^2-45+45=0+45}\\\\\displaystyle{x^2+5y^2=45}$

Convert into the standard form with RHS (Right-Hand Side) equal to 1 by dividing both sides by 45:

$\displaystyle{\dfrac{x^2}{45}+\dfrac{5y^2}{45}=\dfrac{45}{45}}\\\\\displaystyle{\dfrac{x^2}{45}+\dfrac{y^2}{9}=1}$

Therefore, the center of ellipse is at (0,0) since there are no values of h and k.

8 0

1 year ago

BRAINIEST TO WHOEVER RIGHT

Oxana [17]

Answer:

Question 6. M(5, 2)

Question 7. M(-6, 0)

Step-by-step explanation:

1. C(3, -5) and D(7, 9)

Use the midpoint formula:

(x1 + x2/2, y1 + y2/2)

(3 + 7/2, -5 + 9/2)

(10/2, 4/2)

(5, 2)

2. S(-8, -6) and T(-4, 6)

Use the midpoint formula:

(x1 + x2/2, y1 + y2/2)

(-8 + -4/2, -6 + 6/2)

(-12/2, 0/2)

(-6, 0)

7 0

2 years ago

Sergio [31]

$\qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star$