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3 years ago

5

What is the value of StartFraction 1 Over 6 Superscript 0 EndFraction? One-sixth 0 1 undefined

2 answers:

Allisa [31]3 years ago

8 0

Answer:

1

Step-by-step explanation:

just took the test :)

marusya05 [52]3 years ago

5 0

Answer:

1

Step-by-step explanation:

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-0.5x-3.69=x-1.9-2.39

Romashka [77]

-0.5x-3.69 = x+0.49
-0.5x = x + 4.18
-1.5x = 4.18
x = -2.7866666....

8 0

3 years ago

Please make original sentences with the words<br><br> -wallop<br> -diametrically <br> -luminous

Bess [88]

Answer:

-"My step-dad's punch packs a wallop!"

-"The stars shining in the night sky were luminous."

-"The two diametrically opposed viewpoints of ketchup and mustard have been on war for decades."

4 0

3 years ago

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The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

4 years ago

Read 2 more answers

Do these measurements create a triangle? true or false?

Alborosie

Answer:

Question 9: False

Question 10: False

Step-by-step explanation:

The third side is always greater than the other two sides.

<u>Question 9</u>

a = 6, b = 6, c = 5

Since the third side is the smallest, it would not create a triangle.

<u>Question 10</u>

a = 7, b = 2, c = 5

Since the third side is the smallest, it would not create a triangle.

4 0

3 years ago

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Multiply and simplify (x-9)(x-3)

Volgvan

Answer:

x2-12x+3

Step-by-step explanation:

=x(x-3)-9(x-3)

=x2-3x-9x+3

=x2-12x+3

7 0

4 years ago

Read 2 more answers