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Tems11 [23]
3 years ago
15

Find the points of intersection of the circles x²+y²-15=0 and x²-4x+y²+2y-5=0. Check by graphing the equations.

Mathematics
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

The answer to your question is:

Step-by-step explanation:

Solve by elimination

                                           -  x²  -  y²               + 15   =  0

                                             x²   +y²  - 4x + 2y - 5    =  0

                                             0       0   - 4x + 2y + 10 = 0

Solve it for x                          -4x = -2y - 10 ;     x = 1/2y + 5/2

Substitution

                                    ( 1/2y + 5/2)²+ y² - 15=0                      

                                    (y² + 2y + 25)/4 + y² - 15 = 0

                                     y² + 10y + 25 + 4y² - 60 = 0

                                     5y² + 10y - 35 = 0

Solve the equation

                               y1 = -3.83                y2 = 1.83

                             x1 = (5 - 3.83) /2        x2 = (5 + 1.83) / 2

                             x1 = 0.59                    x2 = 3.42

      Point 1 = (0.59 , -3.83)                     Point 2 ( 3.42, 1.83)

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