Find the points of intersection of the circles x²+y²-15=0 and x²-4x+y²+2y-5=0. Check by graphing the equations.
1 answer:
Answer:
The answer to your question is:
Step-by-step explanation:
Solve by elimination
- x² - y² + 15 = 0
x² +y² - 4x + 2y - 5 = 0
0 0 - 4x + 2y + 10 = 0
Solve it for x -4x = -2y - 10 ; x = 1/2y + 5/2
Substitution
( 1/2y + 5/2)²+ y² - 15=0
(y² + 2y + 25)/4 + y² - 15 = 0
y² + 10y + 25 + 4y² - 60 = 0
5y² + 10y - 35 = 0
Solve the equation
y1 = -3.83 y2 = 1.83
x1 = (5 - 3.83) /2 x2 = (5 + 1.83) / 2
x1 = 0.59 x2 = 3.42
Point 1 = (0.59 , -3.83) Point 2 ( 3.42, 1.83)
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Answer:
y =
Step-by-step explanation:
The equation used to find the equation for a line with two intercepts is called point slope form. , where
and
are the intercept points and m is the slope.
However, we need the slope to use this formula.
Use
m = \frac{y_{1} - y_{2} }{x_{1} - x_{2}}
y - ( -7 ) = m ( x - ( 4 ) )
y - ( -7 ) = -7/4 ( x - ( 4 ) )
y + 7 = -7/4 ( x + 4 )
y + 7 =
y + 7 =
y + 7 =
y + 7 = - 7
y =