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yanalaym [24]
3 years ago
10

Which of the following is a reasonable estimated answer to the following problem?

Mathematics
2 answers:
Alex17521 [72]3 years ago
7 0

Answer:

1,000

I did it in my math wok and got it correct

bulgar [2K]3 years ago
4 0
989,867 \approx 1,000,000
999 \approx 1000

\implies  \frac{989,867}{999} \approx  \frac{1,000,000}{1000}
\frac{1,000,000}{1000} = 1000

So the answer is approximately 1000.
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Three times the difference of ten and a number is four.
Paul [167]

Answer:

3 (10-a) = 4 i think

Step-by-step explanation:

7 0
3 years ago
21. In 4 + In(4x - 15) = In(5x + 19)
Alexxx [7]

Answer:

x=-30;\quad \:I\ne \:0

Step-by-step explanation:

In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)

\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\

\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\

\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:

\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0

3 0
3 years ago
Is $5.40 the same as $7.00?
natita [175]

Answer:

5.40 is not the same as 7.00

Step-by-step explanation:

6 0
3 years ago
Find the cost for junior tickets
Marat540 [252]

what is the cost for? ik it's for juniors but what is the topic

4 0
3 years ago
Lee is staying at a hotel. The cost of the first night is $240. The cost for each night after that is $210. Let y represent the
GenaCL600 [577]

A) The situation represents an arithmetic sequence because the successive y-values have a common difference of 210.

F(1) = 240 +210

F(2) = 240 +2(210)

F(3) = 240+3(210)

.

.

.

.

F(x)= 240 +210x.

Learn more about Sequence:

brainly.com/question/12246947

#SPJ4

3 0
2 years ago
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