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ddd [48]
3 years ago
11

There are 18 girls and 12 boys in your class. What is the probability that a new kid entering your class will be a boy

Mathematics
2 answers:
Llana [10]3 years ago
6 0
50 percent because the amount of students already in the class will not affect the new student coming in. So it would be 1/2, .5, or %50
nikdorinn [45]3 years ago
4 0
Its a 50/50 chance. P=0.5
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A picture is 46 cm by 32 cm. A scale diagram of the picture must fit in a space that is 3 m by 2 m. Which scale would be the mos
Marrrta [24]

Answer:

A picture that is 46cm by 32 cm must fit in a space that is 3m by 2m

First, let's rewrite both of these dimensions in the same units.

Knowing that:

1m = 100cm

Then the dimensions of the space can be rewritten from:

3m by 2m

to:

300cm by 200cm

So, if we enlarge our original picture by a scale factor K, the new dimensions of the picture will be:

K*46cm by K*32cm

Now we just need to find a value of K such that:

K*46cm is something near to 300cm

K*32cm is something near to 200cm

First, we can solve the equation:

K*46cm = 300cm

solving this for K we get:

K = 300cm/46cm = 6.5

While if we solve the equation:

K*32cm = 200cm

we get:

K = 200cm/32cm = 6.25

So we got two possible scale factors.

Which one we should take?

Notice that if we wanted to use the larger one (K = 6.5) for the 32cm side. the new length would be:

32cm*6.5 = 208cm

This is larger than the 200cm of space that we have

Then we can not select the larger option, we can only take the other value:

K = 6.25

Then we can conclude that a reasonable scale factor to use is K = 6.25

4 0
2 years ago
Solve for x and graph the solution on the number line
podryga [215]
14 because i did the math and i was right
7 0
2 years ago
I need to know how to solve this
kirza4 [7]
No solution, the answer is no solution
5 0
3 years ago
For Mothers Day, Jim bought 3 hydrangea plants. For Father's Day, he bought two ties. If a tie costs $5 more than a plant and he
den301095 [7]

$16.95 plant

$21.95 tie

6 0
3 years ago
Raj tried to solve the system below.
jekas [21]

Answer: Option C) Raj forgot the negative when substituting -15+9x for y.


Solution:

(1) 9x-y=15

(2) 2x+8y=28

Isolating y in the first equation. Subtracting 9x both sides of the equation:

(1) 9x-y-9x=15-9x

Subtracting:

(1) -y=15-9x

Multiplying both sides of the equation by -1:

(1) (-1)(-y)=(-1)(15-9x)

(1) y=-15+9x

Then Raj found the value of y. It's not option D.

Substitutng y by -15+9x in the second equation:

(2) 2x+8(-15+9x)=28

Then option C) is the answer: Raj forgot the negative when substituting -15+9x for y.

Eliminating the parentheses applying the distributive property in the multiplication:

(2) 2x-120+72x=28

Adding similar terms:

(2) 74x-120=28

Solving for x. Adding 120 both sides of the equation:

(2) 74x-120+120=28+120

Adding:

(2) 74x=148

Dividing both sides of the equation by 74:

(2) 74x/74=148/74

Dividing:

(2) x=2

Solving for y: Replacing x by 2 in the first equation:

(1) y=-15+9x

(1) y=-15+9(2)

Multiplying:

(1) y=-15+18

Subtracting:

(1) y=3  

3 0
3 years ago
Read 2 more answers
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