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Zolol [24]
3 years ago
10

PICTURE HELPPP!!!!! Please please please

Mathematics
1 answer:
Gwar [14]3 years ago
8 0

Answer:

-3

Step-by-step explanation:

divide by both sides by -8 and you get -3.

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What does this mean we never went over it..: Find the difference between 827 and 533. * Please tell me. Thank you!
Nostrana [21]

Answer:

294

Step-by-step explanation:

Difference means subtraction, so you just subtract 533 from 827.

827-533=294

hope this helps! : )

8 0
3 years ago
Read 2 more answers
Lauren is given a 12% pay rise. Her new salary is £24,080
svet-max [94.6K]

Answer:

21,500

Step-by-step explanation:

3 0
3 years ago
A manufacturer of college textbooks is interested in estimating the strength of the bindings produced by a particular binding ma
IrinaVladis [17]

Answer:

538 books should be tested.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many books should be tested to estimate the average force required to break the binding to within 0.08 lb with 99% confidence?

n books should be tested.

n is found when M = 0.08

We have that \sigma = 0.72

M = z*\frac{\sigma}{\sqrt{n}}

0.08 = 2.575*\frac{0.72}{\sqrt{n}}

0.08\sqrt{n} = 2.575*0.72

\sqrt{n} = \frac{2.575*0.72}{0.08}

(\sqrt{n})^{2} = (\frac{2.575*0.72}{0.08})^{2}

n = 537.1

Rounding up

538 books should be tested.

6 0
3 years ago
(3n^2-5n+6) + (-8n^2-3n-2)=
Aleksandr [31]

Answer:

-5n²-8n+4

Step-by-step explanation:

Remove Parentheses :

3n²-5n+6 - 8n²-3n-2

Collect/Combine Like terms:

(3n²-8n²) + (-5n-3n) +(6-2)

Simplify:

-5n²-8n+4

7 0
3 years ago
a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F
slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

               M= (c^2)/8 which is intern equal to 2\sqrt{2}

Step-by-step explanation:

           Find the area, by setting the limits as

               = 4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}4d\theta

                 =8\pi

Therefore;

Mxy=  \int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta

       z-bar = 8/3

M= 8\pi dividing it into two volume gives us = 4\pi

means  4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta

             4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)

              c=2\sqrt{2}

       

                 

                 

5 0
3 years ago
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