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4 years ago

15

PLEASE HELP ME [99 POINTS[

2 answers:

Ierofanga [76]4 years ago

3 0

I think it b havent seen a relation(a)

lisabon 2012 [21]4 years ago

3 0

(B) Nonlinear function

A linear function is a straight line, which, in this case, is not correct.

Relations are not given, for we need to know where each point is, or what equation is being used.

hope this helps

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Can anybody help plzz?? 65 points

Yakvenalex [24]

Answer:

$\frac{dy}{dx} =\frac{-8}{x^2} +2$

$\frac{d^2y}{dx^2} =\frac{16}{x^3}$

Stationary Points: See below.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

<u>Calculus</u>

Derivative Notation dy/dx

Derivative of a Constant equals 0.

Stationary Points are where the derivative is equal to 0.

1st Derivative Test - Tells us if the function f(x) has relative max or mins. Critical Numbers occur when f'(x) = 0 or f'(x) = undef
2nd Derivative Test - Tells us the function f(x)'s concavity behavior. Possible Points of Inflection/Points of Inflection occur when f"(x) = 0 or f"(x) = undef

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

$f(x)=\frac{8}{x} +2x$

<u>Step 2: Find 1st Derivative (dy/dx)</u>

Quotient Rule [Basic Power]: $f'(x)=\frac{0(x)-1(8)}{x^2} +2x$
Simplify: $f'(x)=\frac{-8}{x^2} +2x$
Basic Power Rule: $f'(x)=\frac{-8}{x^2} +1 \cdot 2x^{1-1}$
Simplify: $f'(x)=\frac{-8}{x^2} +2$

<u>Step 3: 1st Derivative Test</u>

Set 1st Derivative equal to 0: $0=\frac{-8}{x^2} +2$
Subtract 2 on both sides: $-2=\frac{-8}{x^2}$
Multiply x² on both sides: $-2x^2=-8$
Divide -2 on both sides: $x^2=4$
Square root both sides: $x= \pm 2$

Our Critical Points (stationary points for rel max/min) are -2 and 2.

<u>Step 4: Find 2nd Derivative (d²y/dx²)</u>

Define: $f'(x)=\frac{-8}{x^2} +2$
Quotient Rule [Basic Power]: $f''(x)=\frac{0(x^2)-2x(-8)}{(x^2)^2} +2$
Simplify: $f''(x)=\frac{16}{x^3} +2$
Basic Power Rule: $f''(x)=\frac{16}{x^3}$

<u>Step 5: 2nd Derivative Test</u>

Set 2nd Derivative equal to 0: $0=\frac{16}{x^3}$
Solve for <em>x</em>: $x = 0$

Our Possible Point of Inflection (stationary points for concavity) is 0.

<u>Step 6: Find coordinates</u>

<em>Plug in the C.N and P.P.I into f(x) to find coordinate points.</em>

x = -2

Substitute: $f(-2)=\frac{8}{-2} +2(-2)$
Divide/Multiply: $f(-2)=-4-4$
Subtract: $f(-2)=-8$

x = 2

Substitute: $f(2)=\frac{8}{2} +2(2)$
Divide/Multiply: $f(2)=4 +4$
Add: $f(2)=8$

x = 0

Substitute: $f(0)=\frac{8}{0} +2(0)$
Evaluate: $f(0)=\text{unde} \text{fined}$

<u>Step 7: Identify Behavior</u>

<em>See Attachment.</em>

Point (-2, -8) is a relative max because f'(x) changes signs from + to -.

Point (2, 8) is a relative min because f'(x) changes signs from - to +.

When x = 0, there is a concavity change because f"(x) changes signs from - to +.

3 0

3 years ago

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umka2103 [35]

Answer:

y=2x+7

Step-by-step explanation:

If you plug in the x and y values, they are correct.

3 0

3 years ago

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There are 60 slices of cheesecake in 5 cheesecakes.If There are the same number of slices in each cheesecake, how many slices ar

aniked [119]

60 slices in 5 cheesecakes. So 1 cheesecake has 12 slices. So 8 cheesecakes will have 96 slices

6 0

3 years ago

Select all the inequalities that have symbols that will be reversed when the variable is isolated.

LenaWriter [7]

Answer:

-4.5c > 9 will have its inequality symbol reversed

-215 ≤ -52d will have its inequality symbol reversed

Step-by-step explanation:

anytime you are multiplying or dividing an inequality by a negative you must reverse the inequality symbol

5 0

3 years ago

What is the sum of the geometric series in which a1 = −5, r = 3, and an = −405?

marysya [2.9K]

An = a1 * r^(n-1)

-405 = -5*3^(n-1)

3^(n-1) = 81

3^4 = 81 so n-1 = 3 and n = 4

Sn = S4 = -5 (1 - 3^4) / ( 1 - 3) = 400 / -2 = -200 Answer

3 0

3 years ago