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4 years ago

How many different 4 letter arrangements can be formed from the letters in the word cards

1 answer:

5 0

Slot method
1st slot, 5 options
2nd slot, 4 options (1 gone to the first slot)
3rd slot, 3 options (1 gone again)
4th slot,2 options (1 less)

multiply
5*4*3*2=120

answer is 120 arrangements

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Is a empty set a subset of every set

Thepotemich [5.8K]

Answer:

Subsets That Make Up the Real Numbers. The set of real numbers is made up of the rational and the irrational numbers. Rational numbers are integers and numbers that can be expressed as a fraction.

8 0

4 years ago

The support of a wood table are in the shape of a right triangle. Find the third angle of the triangle of the measure of one of

Semenov [28]

<h3>The measure of third angle of triangle is 67 degrees</h3>

<em><u>Solution:</u></em>

Given that,

The support of a wood table are in the shape of a right triangle

Since it is a right angle, one of the angle must be $90^{\circ}$

The measure of one of the angles is 23 degrees

To find: third angle angle

We know that,

Sum of all angles in triangle equals 180 degrees

Therefore,

$90^{\circ} + 23^{\circ} + \text{ third angle } = 180^{\circ}\\\\ \text{ third angle } + 113 = 180\\\\ \text{ third angle } = 180 - 113\\\\ \text{ third angle } = 67^{\circ}$

Thus measure of third angle of triangle is 67 degrees

5 0

3 years ago

Find a particular solution to the differential equation y′′+2y′+y=2t2−t+3e−2t. y′′+2y′+y=2t2−t+3e−2t.

Jlenok [28]

$y''+2y'+y=2t^2-t+3e^{-2t}$

The characteristic equation is

$r^2+2r+1=(r+1)^2=0\implies r=-1$

so the characteristic solution is

$y_c=C_1e^{-t}+C_2te^{-t}$

For the particular solution, we can try looking for a solution of the form

$y_p=at^2+bt+c+de^{-2t}$
$\implies{y_p}'=2at+b-2de^{-2t}$
$\implies{y_p}''=2a+4de^{-2t}$

Substituting into the ODE, we have

$(2a+4de^{-2t})+2(2at+b-2de^{-2t})+(at^2+bt+c+de^{-2t})=2t^2-t+3e^{-2t}$
$at^2+(4a+b)t+(2a+2b+c)+de^{-2t}=2t^2-t+3e^{-2t}$
$\implies\begin{cases}a=2\\4a+b=-1\\2a+2b+c=0\\d=3\end{cases}\implies a=2,b=-9,c=14,d=3$

So the general solution to the ODE is

$y=y_c+y_p$
$y=C_1e^{-t}+C_2te^{-t}+2t^2-9t+14+3e^{-2t}$

4 0

3 years ago

You roll a number cube 20 times which scenario is least likely?

Karo-lina-s [1.5K]

Answer:

I think it's A is the answer

4 0

3 years ago

Offering 50 points if someone helps me!! ANSWER QUICK

lisov135 [29]

Answer:

x+2 +x-1 +x+3 =16

3x+4=16

3x=16-4

3x=12

x=12/3

x=4

ST is 4+3 =7

4 0

2 years ago

Read 2 more answers