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madam [21]
3 years ago
12

How many different 4 letter arrangements can be formed from the letters in the word cards

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0
Slot method
1st slot, 5 options
2nd slot, 4 options (1 gone to the first slot)
3rd slot, 3 options (1 gone again)
4th slot,2 options (1 less)

multiply
5*4*3*2=120

answer is 120 arrangements
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Please help with this Math Question...
Nataly [62]

Answer: A

<u>Step-by-step explanation:</u>

f(x) = x³ + 4x² + 7x + 6

possible rational roots are ±{1, 2, 3, 6}

Try x = -2

-2 |   1   4   7   6

   <u>|   ↓  -2  -4  -6</u>

       1    2    3   0 ← remainder is 0 so x = -2 is a root  ⇒  (x + 2) = 0

The factored polynomial x² + 2x + 3 = 0 is not factorable so use the quadratic formula to find the roots.

a=1, b=2, c=3

x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\dfrac{-(2)\pm\sqrt{(2)^2-4(1)(3)} }{2(1)}

x=\dfrac{-2\pm\sqrt{4-12} }{2}

x=\dfrac{-2\pm\sqrt{-8} }{2}

x=\dfrac{-2\pm2i\sqrt{2}}{2}

x = -1 \pm i\sqrt{2}

x = -1 + i\sqrt{2}       x = -1 - i\sqrt{2}

x - (-1 + i\sqrt{2})=0       x - (-1 - i\sqrt{2})=0

The factors are:

(x - 2)[x - (-1 + i\sqrt{2})][x - (-1 - i\sqrt{2})]




5 0
3 years ago
Peter leaves his house and walks 15 meters south, then turns east and walks another 15 meters. How far is he from his house? Rou
Varvara68 [4.7K]
When Peter does this, he is creating two sides of a right-angle triangle. The distance from his house to that point will be the hypotenuse of the triangle thus, to work out the length of the hypotenuse, we have to use Pythagoras Theorem! So:

a² + b² = c²
15² + 15² = c²
225 + 225 = c²
450 = c²
15√2 = c
21.21320344 = c

So, this rounded to the nearest tenth would be:

21.2 meters !


4 0
3 years ago
Jake makes and sells pies. He sells each pie for $5.75. The materials to make each pie costs Jake $4.00. The boxes Jakes put the
Studentka2010 [4]

Answer:

A

Step-by-step explanation:It Said on Usa Test prep

3 0
4 years ago
Twoooooooooooooooooooooooooooo
KatRina [158]

Answer:

n = 60.22

Step-by-step explanation:

Hello

To find Sn, we need to draw out equations for each a₇ and a₁₉

In an arithmetic progression,

Sn = a + (n-1)d

Where Sn = sum of the A.P

a = first term

d = common difference

a₇ = 32

32 = a + (7-1)d

32 = a + 6d ........equation (i)

a₁₉ = 140

140 = a + (19-1)d

140 = a + 18d .........equation (ii)

Solve equation (i) and (ii) simultaneously

From equation (i)

32 = a + 6d

Make a the subject of formula

a = 32 - 6d .....equation (iii)

Put equation (iii) into equation (ii)

140 = (32 - 6d) + 18d

140 = 32 - 6d + 18d

Collect like terms

140 - 32 = 12d

12d = 108

d = 108 / 12

d = 9

Put d = 9 in equation (i)

32 = a + 6(9)

32 = a + 54

a = 32 - 54

a = -22

When Sn = 511

Sn = a + (n - 1)d

Substitute and solve for n

511 = -22 + (n-1) × 9

511 = -22 + 9n - 9

511 = -31 + 9n

511 + 31 = 9n

542 = 9n

n = 542 / 9

n = 60.22

5 0
3 years ago
Estimate. Then find the exact sum or difference<br><br> 6,842<br> +2,981
LekaFEV [45]

Answer: 9823

Step-by-step explanation:

4 0
3 years ago
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