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devlian [24]
3 years ago
8

Is 1/7 greater than all of the following except 1/3 -1 -2 -0.1

Mathematics
2 answers:
AnnZ [28]3 years ago
5 0
Correct answer is 1/3
Elis [28]3 years ago
3 0

Answer:

a. 1/3

Step-by-step explanation:

1/3= .33

1/7= .142

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What’s the answer????
mr_godi [17]

Answer:

The symbol is <

Step-by-step explanation:

1001 is less than 1010 so therefore

1001 is < than 1010 or

1001 < 1010

< is less than, > is greater than, = is equal to

4 0
2 years ago
Read 2 more answers
Martina buys a video game that normally costs d dollars, but it is on sale for 25% off. If the sales tax on the game is 8%, how
NNADVOKAT [17]

25% off means that they are paying 75% of the original price. Multiply d by 75%:

0.75d

Now you need to multiply the price by 1 plus the sales tax to get the total cost:

0.75d x 1.08

Simplify by multiplying 0.75 by 1.08 to get:

0.81d

7 0
2 years ago
What is the missing numerator? (4 points)
kozerog [31]

Answer:

\frac{x}{7} - \frac{3}{8} = \frac{27\\}{56}

Step-by-step explanation:

C

6 x 8 = 32

7 x 3 = 21

32 - 21 = 27

7 0
2 years ago
Of 136 randomly selected adults, 33 were found to have high blood pressure. Construct a 95% confidence interval for the true of
navik [9.2K]

Answer:

The 95% confidence interval of the proportion of all adults that have high blood pressure is 0.17059 < \hat{p} < 0.314695

Step-by-step explanation:

The confidence interval for a proportion is given by the following formula;

CI=\hat{p}\pm z\times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

Where:

x = 33

n = 136

\hat{p} = x/n = 33/136 = 0.243

z value for 95% confidence is 1.96

Plugging in the values, we have;

CI=0.243\pm 1.96\times \sqrt{\frac{0.243(1-0.243)}{136}}

Which gives;

0.17059 < \hat{p} < 0.314695

Hence the 95% confidence interval of the proportion of all adults that have high blood pressure = 0.17059 < \hat{p} < 0.314695

From the above we have;

23.2 < x < 42.798

Since we are dealing with people, we round down as follows;

23 < x < 42.

4 0
2 years ago
Helppppp.. picture attached
tatyana61 [14]
n^2+n\\\\check:\\\\a_1=1^2+1=2\\a_2=2^2+2=6\\a_3=3^2+3=12\\a_4=4^2+4=20
6 0
3 years ago
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