Answer:
system of equations are
y=53x + 10, y=55x
Step-by-step explanation:
y=mx+b where x is the number of tickets purchased and y is the total cost.
We need to frame the equation for each option
Option 1: $53 for each ticket plus a shipping fee of $10
1 ticket cost = 53
So x tickets cost = 53x
shipping fee = $10 so b= 10
So equation becomes y=53x + 10
Option 2: $55 for each ticket and free shipping
1 ticket cost = 55
So x tickets cost = 55x
shipping fee =0 so b= 0
So equation becomes y=55x
Step-by-step explanation:
Although I cannot find any model or solver, we can proceed to model the optimization problem from the information given.
the problem is to maximize profit.
let desk be x
and chairs be y
400x+250y=P (maximize)
4x+3y<2000 (constraints)
according to restrictions y=2x
let us substitute y=2x in the constraints we have
4x+3(2x)<2000
4x+6x<2000
10x<2000
x<200
so with restriction, if the desk is 200 then chairs should be at least 2 times the desk
y=2x
y=200*2
y=400
we now have to substitute x=200 and y=400 in the expression for profit maximization we have
400x+250y=P (maximize)
80000+100000=P
180000=P
P=$180,000
the profit is $180,000
25 because it s a less common denominaor
The answer is (-2,3)
hope you have a great day ;)
Answer:
a = 4.949
b = 4.949
c = 7
Step-by-step explanation:
c ( hypothenuse ) = 7
to find a, use sine
Sine = 
Sine 45 = 
sine of 45 is 0.707
0.707 =
multiplt 7 on both sides:
0.707 x 7 = x 7
a = 4.949
to find b, use cosine
Cosine = 
Cos 45 = 
cos of 45 is 0.707
0.707 =
multiply 7 on both sides:
0.707 x 7 = x 7
b = 4.949
