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3 years ago

Please help!

Mathematics

2 answers:

dem82 [27]3 years ago

6 0

Answer: 6 in.

Step-by-step explanation: If the hexagon is 36 inches and a hexagon has 6 sides, then we do 36/6 to get 6. Hope this helps.

Hatshy [7]3 years ago

3 0

Answer:

each side is 6.

Step-by-step explanation:

a hexagon has six sides and 36 divided by 6 is 6

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Partition a number line from 0 to 1 into sixth decompose 2/6 into 4 equal lengths.

Anon25 [30]

When we partition a number line from 0 to 1 into six, each segment has a length of 1/6 and the segments are:
1/6. 2/6. 3/6, 4/6, 5/6 , 6/6

Breaking 2/6 into 4 equal parts, we get each part equal to 1/12

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3 years ago

Solve for x<br> A) 42<br> B) 40<br> C) 45<br> D) 38

alexgriva [62]

Answer:

x = 40

Step-by-step explanation:

Using similarity theorem, we have the following:

$\frac{24}{24 - 15} = \frac{x}{x - 25}$

Solve for x

$\frac{24}{9} = \frac{x}{x - 25}$

Cross multiply

$24(x - 25) = x(9)$

$24x - 600 = 9x$

Subtract 24x from each side

$- 600 = 9x - 24x$

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Divide both sides by -15

40 = x

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3 0

2 years ago

Luke can paint 91 portraits in a week how many portraits can Luke paint in for weeks

abruzzese [7]

Answer:

364 paintings

Step-by-step explanation:

You should multiply the amount of paintings he makes per week times the amount of weeks (or 91 x 4), and you'll get your answer!

8 0

2 years ago

Read 2 more answers

17 gallons of water are used to completely fill 4 fish tanks. If each tank holds the same amount of water how many gallons will

Kay [80]

Each tank holds 4.25 gallons! 17/4 is 4.25 :) hope this helps!

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2 years ago

A club consisting of 6 juniors and 8 seniors is to be formed from a group of 13 juniors and 16 seniors. How many different clubs

Vilka [71]

Answer: 22,084,920 different clubs

Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

$C = \frac{N!}{(N-K)!*K!}$

For the juniors we have N = 13 and K = 6

$Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716$

For the seniors we have N = 16 and K = 8

$Cs = \frac{16!}{8!8!} = \frac{16*15*14*13*12*11*10*9}{8*7*6*5*4*3*2*1} = 12870$

Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

C = Cj*Cs = 1,716*12,870 = 22,084,920

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3 years ago