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vlabodo [156]
3 years ago
9

7 is added to one-sixth of g

Mathematics
1 answer:
serg [7]3 years ago
6 0

Answer:

g+1/6=7

Step-by-step explanation:

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Can somebody please help me i need this urgently.
sukhopar [10]

Answer:

multiple choice is worth 2

short response is worth 4

Step-by-step explanation:

23x + 10y = 86

28x + 5y = 76

solve by elimination

multiply the top by -1 and the bottom by 2

-23x + -10y = -86

56x + 10y = 152

add them

33x = 66

x = 2

with x = 2 plug x into one of the equations

23x + 10y = 86

23(2) + 10y = 86

46 + 10y = 86

10y = 40

y = 4

x = 2 and y = 4 so

multiple choice is worth 2

short response is worth 4

6 0
2 years ago
Reduce -34/87 to lowest terms.
scoray [572]

I think it is already reduced.

How you a doin?

3 0
3 years ago
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Solve y = x + 6 for x.
elena-s [515]

Answer:

C

Step-by-step explanation:

move the x over

-x+y=6

move the y over

-x = -y+6

times each number by a -

x=y-6

4 0
3 years ago
Read 2 more answers
Help, how would I get my answer for this question?
Maslowich

Answer:

(-4,32)

Step-by-step explanation:

Given points are (-1,-8)

And given transformation is D_4 r_{x-axis}

We will start from left to right.

First transformation is reflection about x-axis.

When we reflect about x-axis (x,y)\ became\ (x,-y)

So, (-1,-8)=[-1,-(-8)]=(-1,8)

Now next transformation is dilation with a factor 4.

If we do dilation with a factor 'k' to the point (x,y)

New co-ordinates after dilation became (kx,ky)

So, (-1,8)\ became\ (-4,32)

8 0
3 years ago
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=4 and BC=3, Find AH, CH and BH.
IRISSAK [1]

Answer:

  • AH = 3.2
  • CH = 1.8
  • BH = 2.4

Step-by-step explanation:  

It can be convenient to compute the length of the hypotenuse of this triangle (AC). The Pythagorean theorem tells you ...

   AC^2 = AB^2 + CB^2

   AC^2 = 4^2 + 3^2 = 16 + 9 = 25

   AC = √25 = 5  

The altitude divides ∆ABC into similar triangles ∆AHB and ∆BHC. The scale factor for ∆AHB is ...

  scale factor ∆ABC to ∆AHB = AB/AC = 4/5 = 0.8  

And the scale factor to ∆BHC is ...  

  scale factor ∆ABC to ∆BHC = BC/AC = 3/5 = 0.6  

Then the side AH is 0.8·AB = 0.8·4 = 3.2

And the side CH is 0.6·BC = 0.6·3 = 1.8  

These two side lengths should add to the length AC = 5, and they do.  

The remaining side BH can be found from either scale factor:    

  BH = AB·0.6 = BC·0.8 = 4·0.6 = 3·0.8 = 2.4

_____  

The sides of interest are ...  

  AH = 3.2

  CH = 1.8

  BH = 2.4

3 0
3 years ago
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