Answer:
To solve the system of equations by substitution:
<u>2x+y=-2</u>
<u>3x-y=7</u>
first solve for y:
2x+y=-2
y=-2x-2
Then plug ^^ equation for y in the other equation
3x-(-2x-2)=7
5x+2=7
5x=5
x=1
Then solve for y:
2(1)+y=-2
y=-4
Final answer is x = 1 and y = -4
Hope it helps!
Answer:
(a) 2ab - a/b
(b) c² + d + 2cd
(c) c + c²
(d) Let x be the number that is 1 greater than b, then x = b + 1
Let y be the number twice as large as b, then y = 2b
Then the quotient of x and y is what we want. This is (b + 1)/2b
(e) pq - 3(p + q)
(f) The quotient of n² and n³ + 5, this is
n²/(n³ + 5)
For a rectangle,
area = length * width
We can solve the equation for width.
width = area/length
Divide the area by the length to find the width.
width = (201.5 in.^2)/(13 in.) = 15.5 in.
Answer: the width is 15.5 in.
