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4 years ago

What is the center of dilation a b c d

Mathematics

1 answer:

galina1969 [7]4 years ago

3 0

Answer:

Step-by-step explanation:

Look at the picture.

Only from point A do the lines pass through the corresponding vertices of both triangles.

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Do two points always, sometimes, or never determine a line? Explain.

mel-nik [20]

Answer: sometimes

explanation:

if there are two points then there could be a line to connect them, however, there could always be two points that are separate on their own.

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3 years ago

Read 2 more answers

What is the x-intercept of the graph 4x-6y=12

charle [14.2K]

So the x-intercept is 3. Also, the y-intercept can also be obtained by putting x=0 in the equation to get y=12/(-6)=-2

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3 years ago

If a(x) = 3x + 1 and 5(x)=1/x-4, what is the domain of (ba)(x)?

kumpel [21]

For this case we have the following fusions:

$a (x) = 3x + 1\\b (x) = \frac {1} {x} -4$

We must find $(a * b) (x):$

By definition:

$(a * b) (x) = a (x) * b (x)\\(a * b) (x) = (3x + 1) * (\frac {1} {x} -4)\\(a * b) (x) = \frac {3x} {x} -12x + \frac {1} {x} -4\\(a * b) (x) = 3-12x + \frac {1} {x} -4\\(a * b) (x) = - 12x + \frac {1} {x} -1$

The domain of the function will be given by all the values for which the function is defined, that is, all real numbers except zero.

Answer:

(-∞, 0) U (0,∞)

5 0

4 years ago

Polygon ABCDE is reflected across the x-axis to form polygon A′B′C′D′E′. Then polygon A′B′C′D′E′ is dilated by a scale factor of

PIT_PIT [208]

Hope this helps
The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2 units up to form polygon - 914438.

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4 years ago

Given a diameter with endpoints P(-12,-8) and Q(0,0),find the center coordinate circumstance and area of the circle described

ra1l [238]

Answer:

Center:(-6,-4)

Circumference:45.31

Area:163.4

Step-by-step explanation:

The given circle has diameter with endpoints P(-12,-8) and Q(0,0).

The center is the midpoint of P(-12,-8) and Q(0,0).

We use the midpoint rule to find the center.