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3 years ago

Find the area of the triangle below.

Mathematics

1 answer:

victus00 [196]3 years ago

3 0

Answer:

You didn't tell me which one is the base or height

Step-by-step explanation:

Area of a triangle: $\frac{1}{2} bh$

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On an alien planet with no atmosphere, acceleration due to gravity is given by g = 12m/s^2. A cannonball is launched from the or

almond37 [142]

Answer:

a) $\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$ , b) $\theta = \frac{\pi}{4}$ , c) $y_{max} = 84.375\,m$ , $t = 3.75\,s$ .

Step-by-step explanation:

a) The function in terms of time and the inital angle measured from the horizontal is:

$\vec r (t) = [(v_{o}\cdot \cos \theta)\cdot t]\cdot i + \left[(v_{o}\cdot \sin \theta)\cdot t -\frac{1}{2}\cdot g \cdot t^{2} \right]\cdot j$

The particular expression for the cannonball is:

$\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$

b) The components of the position of the cannonball before hitting the ground is:

$x = (90\cdot \cos \theta)\cdot t$

$0 = 90\cdot \sin \theta - 6\cdot t$

After a quick substitution and some algebraic and trigonometric handling, the following expression is found:

$0 = 90\cdot \sin \theta - 6\cdot \left(\frac{x}{90\cdot \cos \theta} \right)$

$0 = 8100\cdot \sin \theta \cdot \cos \theta - 6\cdot x$

$0 = 4050\cdot \sin 2\theta - 6\cdot x$

$6\cdot x = 4050\cdot \sin 2\theta$

$x = 675\cdot \sin 2\theta$

The angle for a maximum horizontal distance is determined by deriving the function, equalizing the resulting formula to zero and finding the angle:

$\frac{dx}{d\theta} = 1350\cdot \cos 2\theta$

$1350\cdot \cos 2\theta = 0$

$\cos 2\theta = 0$

$2\theta = \frac{\pi}{2}$

$\theta = \frac{\pi}{4}$

Now, it is required to demonstrate that critical point leads to a maximum. The second derivative is:

$\frac{d^{2}x}{d\theta^{2}} = -2700\cdot \sin 2\theta$

$\frac{d^{2}x}{d\theta^{2}} = -2700$

Which demonstrates the existence of the maximum associated with the critical point found before.

c) The equation for the vertical component of position is:

$y = 45\cdot t - 6\cdot t^{2}$

The maximum height can be found by deriving the previous expression, which is equalized to zero and critical values are found afterwards:

$\frac{dy}{dt} = 45 - 12\cdot t$

$45-12\cdot t = 0$

$t = \frac{45}{12}$

$t = 3.75\,s$

Now, the second derivative is used to check if such solution leads to a maximum:

$\frac{d^{2}y}{dt^{2}} = -12$

Which demonstrates the assumption.

The maximum height reached by the cannonball is:

$y_{max} = 45\cdot (3.75\,s)-6\cdot (3.75\,s)^{2}$

$y_{max} = 84.375\,m$

7 0

3 years ago

What's the length of the hypotenuse

WINSTONCH [101]

Step-by-step explanation:

${c}^{2} = {a}^{2} + {b}^{2} \\ {c}^{2} = {15}^{2} + {15}^{2} \\ {c}^{2} = 450 \\ c = \sqrt{450} = \sqrt{ {15}^{2} \times 2 } = 15 \sqrt{2}$

8 0

3 years ago

What's 4/12 equivalent to if the choices were 14/6 , 3/18 , 1/2 , or 6/18

Thepotemich [5.8K]

Your answer is 4/12 = 6/18

4 0

3 years ago

HELP I ONLY HAVE THESE TWO QUESTIONS LEFT!!!!!!! First, How Many cubic blocks of side length 1/6 inch would it take to fill a cu

Ad libitum [116K]

Answer:

1. There are 8 cubic blocks are needed to fill a cube. Explanation in pic

2. 441 cubic blocks will fill the rectangular prism. Explanation in pic

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

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3 years ago

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What is a slope of a graph

Serhud [2]

It is a vertical change.

Hope this helped.

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