Answer:
cool.
Step-by-step explanation:
Answer:
0.9792
Step-by-step explanation:
Data provided in the question:
Average gross sales = $1,240
Standard deviation = $180
sample size = 40
Now,
standard deviation of sample average
=
=
= 28.46
Now,
z value for 1200 =
= -1.4,
and,
p value for (z = -1.4) = 0.0808
therefore,
P(average < $1200) = 0.0808
Thus,
probability that the average over the next 40 weekdays will exceed $1,200
= 1 - 0.808
= 0.9792
Answer:
a) 0.23
b) The 95% confidence interval for the population proportion is (0.1717, 0.2883).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Point estimate
The point estimate is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the population proportion is (0.1717, 0.2883).
Answer:
<h2>12</h2>
Step-by-step explanation:
<h2>by Pythagoras thm</h2><h2>20square- 16square</h2><h2>you get answer.</h2>
For what? Sorry is there an attachment?