Volume of water in the tank:
Differentiate both sides with respect to time <em>t</em> :
<em>V</em> changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for d<em>h</em>/d<em>t</em> :
(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)
False I think it doesn't add up to 18
I'm very sure the answer would be (4, 64)
Answer: 55-1/2w=p
Step-by-step explanation: 55 is the starting weight. Therefore, you need to subtract 55 by 1/2 (the amount of weight he loses each week) times each week. This will determines the weight- (p).
Answer:
- 2
Step-by-step explanation:
The average rate of change of h(x) in the closed interval [a, b ] is
Here [a, b ] = [1, 8 ], thus
f(b) = f(8) = - 8² + 7(8) + 14 = - 64 + 56 + 14 = 6
f(a) = f(1) = - 1² + 7(1) + 14 = - 1 + 7 + 14 = 20
average rate of change = 
= 
= - 2
