This is the concept of indices. To re-write the question as instructed we proceed as follows:
b^-6×b^11
according to the rules of indices, when we multiply the number which have the same base, we add their powers. In our case this will be:
b^-6×b^11
adding their powers we get:
b^(-6+11)
=b^5
the answer will therefore be b^5
Answer:
The answer is 1,000
SInce the beginning number is 3 and there are ten possible numbers to put in the remaining three slots, there are exactly 1,000 possible combinations for a 3-digit code. The answer is 1,000. There are 3 rows of 10 digits. The number of combinations 10 to the thid power which is 1000 (10 * 10 * 10)
Answer:
yes, sounds linear.
this is an mx + b scenario.
here's the model:
y = )3/1)x + 50
or
y = 3x + 50
where the 1 in the slope denominator is a square foot.
