Answer:
Step-by-step explanation:
Since the coefficient of x^2 is positive, this quadratic is a parabola in the shape of a U, hence has a minimum.
We want to end up with the form (x-h)^2 + c. Since (x-h)^2>=0, this form shows that the minimum is achieved when x=h.
Completing the square will put the quadratic in the desired form. Note that:
(x-h)^2=x^2-2hx+h^2
Comparing this with the given form, we must have -8=-2h, or h=4. But we are missing h^2=4^2=16. We can add the missing 16 and subtract it elsewhere without changing the quadratic.
x^2-8x+16 + (16-4) = (x-4)^2 + 12
Now we know that at x=4 the quadratic has a minimum and that the minimum is 12.
Answer:
yes
Step-by-step explanation:
send the questions....
X(0.25)=143.86
x=143.86/0.25=575.44 (575.44 is the principal amount.
Answer:
are you sure there isn't a 90?
Step-by-step explanation:
Because there are 4 quarters in a whole, so 22 x 4 = 88, and there are 2 quarters in 1/2 so it would be 88+2, which is 90.