3 years ago

If the club decides to send 5 members to the convention, how many different groups of 5 are possible? there are 10 members

1 answer:

7 0

For the 1st member, you have 10 possible choices.

For the 2nd, you have 9 remaining choices.

For the 3rd: 8.

So all possible combinations would be:
10*9*8*7*6 = 10! - 5! = 30,240 combinations.

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In plain text, it is appropriate to express the division using a division bar (/) and parentheses around the numerator and denominator:
(3x^4 +7x^3 +2x^2 +13x +5)/(x^2 +3x +1)

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