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Nikitich [7]
3 years ago
13

If the club decides to send 5 members to the convention, how many different groups of 5 are possible? there are 10 members

Mathematics
1 answer:
hodyreva [135]3 years ago
7 0
For the 1st member, you have 10 possible choices.

For the 2nd, you have 9 remaining choices.

For the 3rd: 8.

So all possible combinations would be:
10*9*8*7*6 = 10! - 5! = 30,240 combinations.
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