A. (4,0)<br> b. (3,2)<br> c. (6,4) <br> d. (0,0)

140% of what number is 39?<br> Provide an exact fraction answer.

Norma-Jean [14]

Answer:

27.86 or 27 wholes 6/7

Step-by-step explanation:

Let the number be x

140% of x = 39

140x/100 = 39

140x = 3900

x= 3900/140

x = 27 wholes 6/7 or 27.86

4 0

3 years ago

Read 2 more answers

"A histogram of a set of data indicates that the distribution of the data is skewed right. Which measure of central tendency wil

sineoko [7]

Answer:

the mean

Step-by-step explanation:

A right skewed histogram is a positive skewed histogram (which means the tail is longer the positive direction) that have its tail to the right.

For a right skewed histogram the mean has a larger value that the median because the peak of the skewness is fall in the median range then the mean follow to the right. and the data drive the mean value to the right which increase in value.

6 0

3 years ago

What is the measure of each angle in a hexagon if the lengths of all six sides are equal?

Tpy6a [65]

Answer:

120 degrees! ^^

Step-by-step explanation:

(Image from Wikipedia-)

7 0

2 years ago

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if you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting one Queen and three king

Elza [17]

Answer: $\frac{16}{270725}$

This is the same as writing 16/270725

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Explanation:

There are 4 ways to draw a queen and 4 ways to select three kings (think of it like saying there are 4 ways to leave a king out). That produces 4*4 = 16 ways total to draw the four cards we want.

This is out of $_{52}C_4 = 270,725$ ways to select four cards without worrying if we got a queen and/or king. The steps to finding this number are shown below.

Divide the two values found to get the final answer $\frac{16}{270725}$

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Scratch Work:

Computing the value of $_{52}C_4$

Plug in n = 52 and r = 4 into the combination formula below

$_{n} C _{r} = \frac{n!}{r!*(n-r)!}\\\\_{52} C _{4} = \frac{52!}{4!*(52-4)!}\\\\_{52} C _{4} = \frac{52*51*50*49*48!}{4!*48!}\\\\_{52} C _{4} = \frac{52*51*50*49}{4!} \ \ \text{ .... the 48! terms cancel}\\\\_{52} C _{4} = \frac{52*51*50*49}{4*3*2*1}\\\\_{52} C _{4} = \frac{6,497,400}{24}\\\\_{52} C _{4} = 270,725\\\\$