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Verizon [17]
3 years ago
6

In triangle PQR line segment PQ = 7.2 and line segment QR = 5.2. Which measure cannot be line segment PR?

Mathematics
1 answer:
slavikrds [6]3 years ago
7 0
It's thirteen because it is too large.
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Given f(x)=x3 and g(x)= 1-5x2, fine (fog)(x) and it’s Domain
andre [41]

Answer:

Option B. f(g(x)) = (1-5x ^ 2) ^ 3  all real numbers

Step-by-step explanation:

We have

f(x) = x ^ 3 and g(x) = 1-5x ^ 2

They ask us to find

(fog)(x) and it's Domain

To solve this problem we must introduce the function g(x) within the function f(x)

That is, we must do f(g(x)).

So, we have:

f(x) = x ^ 3

g(x) = 1-5x ^ 2

Then:

f(g(x)) = (1-5x ^ 2) ^ 3

The domain of the function f(g(x)) is the range of the function g(x) = 1-5x ^ 2.

Since the domain and range of g(x) are all real numbers then the domain of f(g(x)) are all real numbers

Therefore the correct answer is the option b: f(g(x)) = (1-5x ^ 2) ^ 3

And his domain is all real.

5 0
3 years ago
Read 2 more answers
HELP PLEASEEEEE I'll give you a crown
arlik [135]

Answer:

8.64%

Step-by-step explanation:

Write it as a decimal

7/81 = 0.0864

0.0864 is the decimal representation for 7/81

For Percentage Conversion :

step 1 To represent 0.0864 in percentage, write 0.0864 as a fraction

Fraction = 0.0864/1

step 2 multiply 100 to both numerator & denominator

(0.0864 x 100)/(1 x 100) = 8.64/100

8.64% is the percentage representation for 7/81

4 0
3 years ago
1.2x + 3 =4x + 2
Dmitry_Shevchenko [17]
1. 2x+3=4x+2
  ⇒ 4x-2x=3-2
2x=1
x=1/2
There is one solution.

2. 18p-10p=5+6/2
8p=5+3
8p=8
p=8:8
p=1

3. 6a/3=2a
2a-a= -2 -3
a= - 5

4. 5+r-2=9,
 5-2+r=9
3+r=9
r=9 - 3
    r=6

5. -0,9 m= 9
     m= - 10

6. -2 (x+1/4)=5-1=4
     x+1/4= -2
     x= -2 - 1/4
     x= -8/4 - 1/4= - 9/4

7. 6f+4f= 6 + 12
    10 f = 18
      f=18/10=1,8

8. 7n - 3n= 16
    4n=16
    n=16:4
    n=4

9. 1/3m-5/6m= - 15 - 3
     2/6 m-5/6=-18
     - 3/6m=-18  ⇒ 1/2m=18
       m=2*18=36
     
7 0
3 years ago
Sara and Paul are on opposite sides of a building that a telephone pole fell on. The pole is leaning away from Paul at
r-ruslan [8.4K]

Answer:

a) See figure attached

b) x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft

c) h = 35 sin (59) = 30.0 ft

So then the heigth for the building is approximately 30 ft

Step-by-step explanation:

Part a

We can see the figure attached is a illustration for the problem on this case.

Part b

For this case we can use the sin law to find the value of r first like this:

\frac{sin(22)}{35 ft} =\frac{sin(59)}{r}

r= \frac{sin(59)}{sin(22)} 35 ft = 80.086ft

Then we can use the same law in order to find the valueof x liek this:

\frac{sin(124)}{x ft} =\frac{sin(34)}{80.086}

x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft

And that represent the distance between Sara and Paul.

Part c

For this cas we are interested on the height h on the figure attached. We can use the sine indentity in order to find it.

sin (59) = \frac{h}{35}

And if we solve for h we got:

h = 35 sin (59) = 30.0 ft

So then the heigth for the building is approximately 30 ft

5 0
3 years ago
Solve for x. Show the equation you used and your work.
kirza4 [7]
ST/VT = UT/WT6+14/14  = (x+4)+21/21X= 20*21/14 - 21x=420/14-25X=30-25x=5
3 0
4 years ago
Read 2 more answers
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