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Mumz [18]
2 years ago
6

Can someone pls help me

Mathematics
1 answer:
netineya [11]2 years ago
4 0

Answer:

? what do u want me todo

Step-by-step explanation:

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5/6 :))))))))))))))))))))
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What is the reciprocal for 2 2/5​
wariber [46]

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5/12

Step-by-step explanation:

2 2/5 = 12/5 so its reciprocal is 5/12

Reciprocals are fractions that are basically "flipped". You flip the denominator to the numerator and vice versa.

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An automobile manufacturer would like to know what proportion of its customers are not satisfied by the service provided by the
zheka24 [161]

Answer:

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Past studies suggest this proportion will be about 0.15

This means that p = 0.15

Find the sample size needed if the margin of error of the confidence interval is to be about 0.04

This is n when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.15*0.85}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.15*0.85}

\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.04})^{2}

n = 17.5

Rounding up

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

8 0
3 years ago
Write a numerical expression for the verbal expression.
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=>(22-6)/5+3 ( numerical expression)

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3 years ago
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Anybody can help me
Lyrx [107]

Answer:

y = 3x + 1

The ? is 3

Enter the numbers into the equation:

Enter (0,1) --> 1 = 0 + 1 --> 1 = 1

Enter (3,10) --> 10 = 3 · 3 + 1 --> 10 = 9 + 1 --> 10 = 10

8 0
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