The page numbers are 10 and 11
Rearrange slightly...
12xy-8y-9x+6 now factor 1st and 2nd pair of terms
4y(3x-2)-3(3x-2)
(4y-3)(3x-2)
15c+10d that’s the answer
When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= ± sqrt(144)= ± 12
So in order that the given equation has double roots, the possible values of b are ± 12.
Answer:
-17y + 16x
Step-by-step explanation:
-3(3y - 2x) + 2(5x - 4y) = -9y + 6x + 10x - 8y = -17Y + 16X.
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