In the word "boogaboo", there are eight (8) letters while there are only four distinct letters. The number of distinct ordered arrangements can be calculated through the equation,
n = 8!/(2!)(4!)
where there are 2 letter b's and 4 letter o's. The answer to this item is 840.
Answer: 840
Answer:
This type of data is called Box and Whisker plots
Step-by-step explanation:
This type of data tells you the range of the data as well as the inner quartile range as it shows the minimum, maximum, median, and Q1 and Q3.
Are those the only answer choices?
Answer:
x > -7 (Hey man think before ask)
Step-by-step explanation:
It is so easy .....
Answer:
a) 229 and 305 days
b) 229 days or less
c) 305 days or more
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 267
Standard deviation = 19
(a) Between what values do the lengths of the middle 95% of all pregnancies fall?_____________and___________days
By the Empirical rule, 95% of all pregnancies fall within 2 standard deviations of the mean.
So
267 - 2*19 = 229 days
to
267 + 2*19 = 305 days
(b) How short are the shortest 2.5% of all pregnancies?______days or less
95% of all pregnancies fall within 2 standard deviations of the mean. The other 5% are more than 2 standard deviations from the mean. Since the distribution is symmetric, 2.5% is more than 2 standard deviations below the mean(shortest 2.5%) and 2.5% is more than 2 standard deviations above the mean(longest 2.5%). So
267 - 2*19 = 229 days
c) How long do the longest 2.5% of pregnancies last?________days or more
Explanation in b)
267 + 2*19 = 305 days
