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Vanyuwa [196]
3 years ago
6

The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both increased by 2

, the fraction is now equal to 2/3 . If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?
Mathematics
1 answer:
mario62 [17]3 years ago
7 0

The two equation which can be used to solve the problem are:

5n - 3d = 0 and 3n - 2d = -2

<h3><u>Solution:</u></h3>

The numerator of the fraction is "n" and the denominator of the fractions is "d"

<em><u>The numerator and denominator of a fraction are in the ratio of 3 to 5</u></em>

numerator : denominator = 3 : 5

\frac{numerator}{denominator} = \frac{3}{5}

\frac{n}{d} = \frac{3}{5}

On cross-multiplication we get,

5n = 3d

<h3>5n - 3d = 0</h3>

This is our first equation

The numerator and denominator are both increased by 2, the fraction is now equal to 2/3

The new numerator will be n + 2 and denominator will be d + 2

\frac{n + 2}{d + 2} = \frac{2}{3}

On cross multiplication we get,

3(n + 2) = 2(d + 2)

3n + 6 = 2d + 4

<h3>3n - 2d = -2</h3>

This is our second equation

Thus the two equation which can be used to solve the problem are:

5n - 3d = 0 and 3n - 2d = -2

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Ollie earns a fixed amount of $2,700 per month and a commission of 12% on all of his sales for the month. To cover all of his ex
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Part A) 0.12x+2,700\geq 5,400

Part B) see the explanation

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Part A) Write an inequality that will represent the amount of sales Ollie will need in order to cover his monthly expenses

Let

x ----> the amount of sales monthly

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The fixed amount of $2,700 plus the commission of 12% on all of his sales for the month must be greater than or equal to $5,400

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Part B) Find the solution and describe what the graph would look like on a number line

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0.12x+2,700\geq 5,400

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0.12x \geq 5,400-2,700\\0.12x \geq 2,700

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The minimum amount of sales needed to cover his monthly expenses is $22,500

In a number line the solution is the shaded area at right of x=22,500 (closed circle)

see the attached figure to better understand the problem

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