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san4es73 [151]
3 years ago
12

Hexagon ABCDEF → hexagon A'B'C'D'E'F' How can the transformation shown be described?

Mathematics
1 answer:
Gekata [30.6K]3 years ago
5 0

Answer:

nonrigid transformation

stretch

Step-by-step explanation:

please add options.

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Ancy
iris [78.8K]

Answer: 18:6

Step-by-step explanation:

5 0
3 years ago
12 chocolate bars for $22 or 20 chocolate bars for $33 use unit rate to determine the better buy.
jekas [21]
12c=22
6c=11
c=1 5/6
20c=33
c= 1 13/20
5/6 is about .83
13/20 is .65
12 chocolate bars for $22 is about $1.83 each
20 chocolate bars for $33 is $1.65 each

The 20 chocolate bars for $33 dollars has a better unit rate and is a better buy.
6 0
3 years ago
On a number line what is the distance between-3/7 and -2/3
Nikitich [7]
Is simply their difference,

\bf -\cfrac{3}{7}-\left( -\cfrac{2}{3} \right)\implies -\cfrac{3}{7}+\cfrac{2}{3}\impliedby \textit{LCD of 21}\implies \cfrac{-3(3)+2(7)}{21}
\\\\\\
\cfrac{-9+14}{21}\implies \cfrac{5}{21}

4 0
3 years ago
Perform the indicated operation. Be sure the answer is reduced.
avanturin [10]
<h3>Given Equation:-</h3>

\boxed{ \rm  \frac{4x^{2}y^{3}z}{9} \times  \frac{45y}{8 {x}^{5} {z}^{5} }}

<h3>Step by step expansion:</h3>

\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times  \dfrac{45y}{8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times  \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times  \dfrac{45y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times  \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y \times  {y}^{3} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y {}^{0}  \times  {y}^{3 + 1} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5 \times  {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \bf  \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}

8 0
2 years ago
Please help if you know the answer please!
quester [9]
36 I believe.....................
7 0
3 years ago
Read 2 more answers
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