Answer:
Step-by-step explanation:
Hello!
The experiment was designed to proof if the physiological blind spot can be reduced with eye training.
One sample of n people was taken and the physiological blind spot was measured. After that, the people selected underwent 3 weeks of eye training and their physiological blind spot was measured again. At the end of the experiment you have two sets of data for the sample, let's call X₁: physiological blind spot of one person before taking eye training", the measurements were taken before the training will correspond to this variable, and X₂: physiological blind spot of one person after three weeks of eye training" the second measurements correspond to this variable.
In this type of situation, where only one sample is taken and both variables are measured to the same observational unit (there is a pair of observations for each person), the observations are dependant and the corresponding test is the paired samples t-test.
To analyze the information you need to create a new variable, usually symbolized as Xd, that will be the difference between X₁ and X₂.
So your response variable would be
Xd: "Difference between a physiological blind spot of one person before taking eye training and physiological blind spot of after three weeks of eye training"
Xd= X₁ - X₂
The study parameter will be the mean of the variable "difference" μd.
I hope it helps!
Answer:B
Step-by-step explanation:I hope it help
Answer:
702
Step-by-step explanation:
The total number of Fish in the aquarium is got by adding up the
Number of Salt Water Fish, and
Number of Fresh water Fish
Number of Salt water Fish = 483
Number of Fres hwater Fish = 358
Total Fish in Aquarium = 483 + 358 = 841
Later, 139 were moved to a new aquarium, the number of fish remaining is 841 MINUS 139. That is:
841 - 139 = 702 fish remaining now
I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.
Answer:
2? The last one
Step-by-step explanation:
