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Lostsunrise [7]

3 years ago

15

the formula for the total surface area of a cylinder is S=2pir^2 + 2pirh. Explain how you could use the distributive property to

write the formula in another way

1 answer:

Ivahew [28]3 years ago

7 0

You undistribute like
ab+ac=a(b+c) so

2pir^2+2pirh=(2pir)(r)+(2pir)(h)=2pir(r+h)

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Last year a state university received 3,560 applications from boys,of those applications,35%were from boys who lived in other st

Aleksandr [31]

$\frac{3560}{x} = \frac{40}{100}$ 40x=356000 x= 8900 applications

you make x the number of total applications

3 0

3 years ago

I don't know how to do this

Gre4nikov [31]

Answer:

x = -11/5 and y = 24/5

Step-by-step explanation:

Use elimination.

First, we need to multiply so that at least one variable can cancel out.

We can multiply the top equation by 2.

So we get

4x + 6y = 20

Then, we can use elimination.

The x's cancel out.

So we get 5y = 24

Or y = 24/5

Then, we can plug in this y value back into the first equation to find x.

2x + 3(24/5) = 10

2x + 72/5 = 50/5

2x = -22/5

x = -11/5

So x = -11/5 and y = 24/5

5 0

2 years ago

WILL GIVE BRAINLIEST PLEASE ANSWER If a circle is dilated by 5/3 and the area of the larger circle is 100pi square cm, then what

Simora [160]

Answer:

We have a small circle, that is dilated by a factor of 5/3 creating a larger circle.

If the smaller circle has a diameter D, then after the dilation, the larger circle will have a diameter equal to: (5/3)*D

We know that the area of the larger circle is:

A = 100*pi cm^2.

And the area of a circle of diameter d, is:

a = pi*(d/2)^2

knowing that the diameter of the large circle is (5/3)*D, we can find the value of D.

A = pi*( (5/3)*D/2)^2 = 100*pi cm^2

let's solve this for D:

pi*( (5/3)*D/2)^2 = 100*pi cm^2

( (5/3)*D/2)^2 = 100 cm^2

( (5/3)*D/2) = √(100 cm^2) = 10cm

D/2 = (3/5)*10cm

D = 2*(3/5)*10cm = 12cm.

Then the area of the smaller circle will be:

a = pi*(D/2)^2 = pi*(12cm/2)^2 = pi*(6cm)^2 = pi*36 cm^2

and pi = 3.14

a = pi*36 cm^2 = 3.14*36cm^2 = 113.04 cm^2

7 0

2 years ago

X² +10x+3=0<br><br>how do I slove it with the quadratic formula?

puteri [66]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find the vertical and horizontal asymptotes, domain, range, and roots of f (x) = -1 / x-3 +2.

gladu [14]

Answer:

Vertical asymptote: $x=3$

Horizontal asymptote: $f(x) =2$

Domain of f(x) is all real numbers except 3.

Range of f(x) is all real numbers except 2.

Step-by-step explanation:

Given:

Function:

$f (x) = -\dfrac{1 }{ x-3} +2$

One root, $x = 3.5$

To find:

Vertical and horizontal asymptote, domain, range and roots of f(x).

Solution:

First of all, let us find the roots of f(x).

<em>Roots of f(x) means the value of x where f(x) = 0</em>

$0= -\dfrac{1 }{ x-3} +2\\\Rightarrow 2= \dfrac{1 }{ x-3}\\\Rightarrow 2x-2 \times 3=1\\\Rightarrow 2x=7\\\Rightarrow x = 3.5$

One root, $x = 3.5$

Domain of f(x) i.e. the values that we give as input to the function and there is a value of f(x) defined for it.

For x = 3, the value of f(x) $\rightarrow \infty$

For all, other values of $x$ , $f(x)$ is defined.

Hence, Domain of f(x) is all real numbers except 3.

Range of f(x) i.e. the values that are possible output of the function.

f(x) = 2 is not possible in this case because something is subtracted from 2. That something is $\frac{1}{x-3}$ .

Hence, Range of f(x) is all real numbers except 2.

Vertical Asymptote is the value of x, where value of f(x) $\rightarrow \infty$ .

$-\dfrac{1 }{ x-3} +2 \rightarrow \infty$

It is possible only when

$x-3=0\\\Rightarrow x=3$

$\therefore$ vertical asymptote: $x=3$

Horizontal Asymptote is the value of f(x) , where value of x $\rightarrow \infty$ .

$x\rightarrow \infty \Rightarrow \dfrac{1 }{ x-3} \rightarrow 0\\\therefore f(x) =-0+2 \\\Rightarrow f(x) =2$

$\therefore$ Horizontal asymptote: $f(x) =2$

Please refer to the graph of given function as shown in the attached image.

5 0

3 years ago