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3 years ago

I need help on my homework! 50 points.

Mathematics

1 answer:

Rzqust [24]3 years ago

5 0

Dhdghcdgfgfghdfghfyhfhfhfhfhfh

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An estimate cost should always include?

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3 years ago

What is the simplest form of 67/100?

Dafna1 [17]

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3 years ago

Simplify: 40x7- (-12x7) Enter the original expression if it cannot be simplified.

fredd [130]

Answer:

52x^7

Step-by-step explanation:

40x^7 -(-12x^7) =

= 40x^7 + 12x^7 =

= 52x^7

Hope this helps!

If not, I am sorry.

Please mark brainliest if correct!

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2 years ago

Is this correct? if not does anybody know which one it is

erik [133]

You are right thank me later lol

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3 years ago

Read 2 more answers

3/2 x 4/3 x 5/4… x 2006/2005

Lady_Fox [76]

Answer:

1003

Step-by-step explanation:

The problem is a classic example of a telescoping series of products, a series in which each term is represented in a certain form such that the multiplication of most of the terms results in a massive cancelation of subsequent terms within the numerators and denominators of the series.

The simplest form of a telescoping product $a_{k} \ = \ \displaystyle\frac{t_{k}}{t_{k+1}}$ , in which the products of n terms is

$a_{1} \ \times \ a_{2} \ \times \ a_{3} \ \times \ \cdots \times \ a_{n-1} \ \times \ a_{n} \ = \ \displaystyle\frac{t_{1}}{t_{2}} \ \times \ \displaystyle\frac{t_{2}}{t_{3}} \ \times \ \displaystyle\frac{t_{3}}{t_{4}} \ \times \ \cdots \ \times \ \displaystyle\frac{t_{n-1}}{t_{n}} \ \times \ \displaystyle\frac{t_{n}}{t_{n+1}} \\ \\ \-\hspace{5.55cm} = \ \displaystyle\frac{t_{1}}{t_{n+1}}.$ .

In this particular case, $t_{1} \ = \ 2$ , $t_{2} \ = \ 3$ , $t_{3} \ = \ 4$ , ..... , in which each term follows a recursive formula of $t_{n+1} \ = \ t_{n} \ + \ 1$ . Therefore,

$\displaystyle\frac{t_{2}}{t_{1}} \times \displaystyle\frac{t_{3}}{t_{2}} \times \displaystyle\frac{t_{4}}{t_{3}} \times \cdots \times \displaystyle\frac{t_{n}}{t_{n-1}} \times \displaystyle\frac{t_{n+1}}{t_{n}} \ = \ \displaystyle\frac{3}{2} \times \displaystyle\frac{4}{3} \times \displaystyle\frac{5}{4} \times \cdots \times \displaystyle\frac{2005}{2004} \times \displaystyle\frac{2006}{2005} \\ \\ \-\hspace{5.95cm} = \ \displaystyle\frac{2006}{2} \\ \\ \-\hspace{5.95cm} = 1003$

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3 years ago