the arc length is calculated by the formula
then
or it can be calculated using the circumference of the circle since we have a semicircle the circumference 2πr must be divided by 2 С=2πr:2=πr =8π=<u>25,12</u>
Answer:
$48.60
Step-by-step explanation:
4 7/5 is a funny way to express a fraction... but anway..... if this is correct, then the answer is as follows:
5/6 kg ------> cost $7.50
1 kg ----> costs $7.50 ÷ 5/6 kg = $9
4 7/5 kg ------> costs $9 x (4 7/5) = $9 x (27/5) = $48.60
Answer:
Step-by-step explanation:
(x^2 - 4)(x^2 - 4)
Simplifying
(x2 + -4)(x2 + -4)
Reorder the terms:
(-4 + x2)(x2 + -4)
Reorder the terms:
(-4 + x2)(-4 + x2)
Multiply (-4 + x2) * (-4 + x2)
(-4(-4 + x2) + x2(-4 + x2))
((-4 * -4 + x2 * -4) + x2(-4 + x2))
((16 + -4x2) + x2(-4 + x2))
(16 + -4x2 + (-4 * x2 + x2 * x2))
(16 + -4x2 + (-4x2 + x4))
Combine like terms: -4x2 + -4x2 = -8x2
(16 + -8x2 + x4)
Answer: The correct option is (B) less than 2.
Step-by-step explanation: Given that Y varies directly with X and has a constant rate of change of 6.
We are to find the possible value of X when the value of Y is 11.
Since Y varies directly with X, so we can write
![Y\propto X\\\\\Rightarrow Y=kx~~~~~~~~~~~~~~~(i),~~~~~~~~~\textup{[where 'k' is the constant of variation]}](https://tex.z-dn.net/?f=Y%5Cpropto%20X%5C%5C%5C%5C%5CRightarrow%20Y%3Dkx~~~~~~~~~~~~~~~%28i%29%2C~~~~~~~~~%5Ctextup%7B%5Bwhere%20%27k%27%20is%20the%20constant%20of%20variation%5D%7D)
Since the rate of change is constant and is equal to 6, so we must have

So, from equation (i), we have

Now, when Y = 11, then from equation (ii), we get

Thus, the value of X is less than 2 when Y = 11.
Option (B) is CORRECT.