Please indicate exponentiation using " ^ " Thanks.
f(x)=x2+14x+40 => <span>f(x)=x^2+14x+40
Next, complete the square:
</span>f(x)=x^2+14x+ 49 - 49 +40 = (x+7)^2 - 9
Write this in the form y = (x+7)^2 - 9 or y + 9 = (x+7)^2
Comparing this result to y = a(x-h)^2 + k, we see that h = -7 and k=-9
In vertex form, the equation is y + 9 = (x+7)^2 and the vertex is at (-7, -9).
Answer:
=0.000342
Standard form is 3.4237×10
Step-by-step explanation:
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101/32 or 3 5/32 or 3.15625
(5/4 × 54/48) = 45/32
(5/4 × 105/75) = 7/4
7/4 x 8 top & bottom =56/32
45+56=101
Hope this helps!
1. The point where x and y axis meet is the intersect, origin of the coordinate system (0,0)
2. m<A and m<D = 90 then <A and D are complementary angles
3. 180 angle or linear rays
4. Obtuse angle measure more than 90
5. Segment of equal lengths are congruent segments
6. Lines that meet at a 90 angle are perpendicular
Answer:
No, a regular pentagon does not tessellate.
In a tessellation, all the angles at a point have to add to 360 degrees, as this means there is no overlap, nor are there gaps. To find the interior angle sum of a pentagon, we use the following formula:
(n-2)*180 (where n is the number of sides)
We plug in the number of sides (5) and get:
Angle sum = (5–2)*180
Angle sum = 3*180
Angle sum = 540
Regular pentagons have equal sides and equal angles, so to find the size of the interior angle of a pentagon, we divide the angle sum by 5 and get 108 degrees for every angle.
As I said before, the angles at a point need to add up to 360, so we need to know if 108 divides evenly into 360. If it does, the shape tessellates, and, if it doesn’t, the shape does not.
360/108 = 3.33333…
This means that a regular pentagon does not tessellate.
Hope this helps!
