¿cual es el perimetro total de un paralelogramo obicuo cuya base mide 2∛54x² cm , y cuyo lado oblicuo mide 3∛54x²?

Mathematics

2 answers:

Step2247 [10]3 years ago

6 0

Answer:

$p=10\sqrt[3]{54}x^2$

Step-by-step explanation:

We are given parallelogram

Since, two opposite sides of any parallelogram are always equal

Let's assume first side =a

second side =b

so, we get

$a=2\sqrt[3]{54}x^2$

$b=3\sqrt[3]{54}x^2$

now, we can find perimeter

perimeter=2a+2b

so, we get

$p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)$

we can simplify it

$p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2$

$p=10\sqrt[3]{54}x^2$ ................Answer

Olin [163]3 years ago

3 0

The perimeter of the parallelogram whose base measure is $2\sqrt[3]{{54}}{x^2}{\text{ cm}}$ and whose oblique side is $3\sqrt[3]{{54}}{x^2}{\text{ cm}}$ is $\boxed{10\sqrt[3]{{54}}{x^2}{\text{ cm}}}.$

Further explanation:

The perimeter of the parallelogram can be expressed as follows,

$\boxed{{\text{Perimeter}} = 2 \times \left( {x + y} \right)}$

Given:

The base measure of the parallelogram is $2\sqrt[3]{{54}}{x^2}{\text{ cm}}.$

The oblique measure of the parallelogram is $3\sqrt[3]{{54}}{x^2}{\text{ cm}}.$

Explanation:

Consider the base measure of the parallelogram be “x”.

Consider the oblique side of the parallelogram as “y”.

The value of $x = 2\sqrt[3]{{54}}{x^2}{\text{ cm}}.$

The value of $y = 3\sqrt[3]{{54}}{x^2}{\text{ cm}}.$

The perimeter of the parallelogram can be obtained as follows,

$\begin{aligned}{\text{Perimeter}} &= 2x + 2y\\&= 2\left( {x + y} \right)\\&= 2\left( {2\sqrt[3]{{54}} + 3\sqrt[3]{{54}}} \right)\\&= 2\left( {5\sqrt[3]{{54}}} \right)\\&= 10\sqrt[3]{{54}}\\\end{aligned}$

The perimeter of the parallelogram whose base measure is $2\sqrt[3]{{54}}{x^2}{\text{ cm}}$ and whose oblique side is $3\sqrt[3]{{54}}{x^2}{\text{ cm}} \:{\text{is} \:\boxed{10\sqrt[3]{{54}}{x^2}{\text{ cm}}}.$