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saw5 [17]
3 years ago
6

Please help me with number 10

Mathematics
1 answer:
Serggg [28]3 years ago
8 0
Water treaded is the biggest and Springtail is the smallest.
Hope it helped
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I need help with this problem PLEASE HELP
xxTIMURxx [149]

The domain of the function is: {-5, -3, -1, 1}

The range of the function is: {-5, -3, -1, 1}

<h3>How to Determine the Range and the Domain of a Function?</h3>

In any given graph that represents a function, the possible set of domain values are plotted on the x-axis (horizontal axis), while the possible set of corresponding range values are plotted on the y-axis (vertical axis).

Thus, the set of x-values (input values) on a graph is the domain of the function while the set of y-values (output values) is the range of the function.

In the given graph, the set of x-values are: -5, -3, -1, and 1.

The set of y-values are: -5, -3, -1, and 1.

Therefore:

The domain of the function is: {-5, -3, -1, 1}

The range of the function is: {-5, -3, -1, 1}

Learn more about the domain and range of a function on:

brainly.com/question/10197594

#SPJ1

7 0
2 years ago
Find the y intercept and x of the following linear equation 3/4x-2y=5
Ira Lisetskai [31]
Just go ahead and subtract 3/4x and bring it to the other side so it should look like this -2y=5-3/4x then go ahead and divide with negative two
8 0
3 years ago
The product of 4 and – 7, added to – 12 .
lina2011 [118]
I think the answer is -40
5 0
3 years ago
Is this correct ? PERPENDICULAR GRAPHS QUESTION
sattari [20]

Answer:

Step-by-step explanation:

Yup its correct :)

7 0
3 years ago
Kirk’s average driving speed is 5 kilometers per hour faster than Thor’s. In the same length of time it takes Kirk to drive 525
Alenkinab [10]
Let K and T be the speeds of Kirk and Thor respectively.

Note the standard definition that d=vt, distance equals velocity times time.

t=d/v

For Kirk, t=525/(T+5)

For Thor, t=490/T

Since we are told that they have traveled the same amount of time we can say t=t which leaves us:

525/(T+5)=490/T  multiply both sides by T

525T/(T+5)=490  multiply both sides by T+5

525T=490T+2450  subtract 490T from both sides

35T=2450  divide both sides by 35

T=70

So Thor's average speed is 70kph, since K=T+5

K=75kph

So Kirk's average speed is 75kph
5 0
3 years ago
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