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babymother [125]
2 years ago
12

Given that tangent theta = negative 1, what is the value of secant theta, for StartFraction 3 pi Over 2 EndFraction less-than th

eta less-than 2 pi?
Mathematics
2 answers:
Elanso [62]2 years ago
7 0

Answer:

The answer is \sqrt{2

Step-by-step explanation:

I took the quiz on edge and got a 100

Rashid [163]2 years ago
6 0

Answer:

sec(\theta)=\frac{2}{\sqrt{2} }=\sqrt{2}

Step-by-step explanation:

Start by noticing that the angle \theta is on the 4th quadrant (between \frac{3\pi}{2} and 2\pi. Recall then that in this quadrant the functions tangent and cosine are positive, while the function sine is negative in value. This is important to remember given the fact that tangent of an angle is defined as the quotient of the sine function at that angle divided by the cosine of the same angle:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Now, let's use the information that the tangent of the angle in question equals "-1", and understand what that angle could be:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-1=\frac{sin(\theta)}{cos(\theta)}\\-cos(\theta)=sin(\theta)

The particular special angle that satisfies this (the magnitude of sine and cosine the same) in the 4th quadrant, is the angle \frac{7\pi}{4}

which renders for the cosine function the value \frac{\sqrt{2} }{2}.

Now, since we are asked to find the value of the secant of this angle, we need to remember the expression for the secant function in terms of other trig functions: sec(\theta)=\frac{1}{cos(\theta)}

Therefore the value of the secant of this angle would be the reciprocal of the cosine of the angle, that is: sec(\theta)=\frac{2}{\sqrt{2} }=\sqrt{2}

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14n + p – 6n = 16p solve for and please explain
mina [271]

Answer:

14n+p-6n=16p

8n+p=16p

8n=15p

This doesn't really make sense,but this is what I got

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3 years ago
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3 years ago
What is 17/20 - 4/15
Zinaida [17]

Hello there, today you gave us the problem \frac{17}{20}-\frac{4}{15},

Our first step is to give them common denominators, which is \frac{51}{60}-\frac{16}{60}, solve it and we get \frac{35}{60} as our answer, which can be simplified down to \frac{7}{12}

4 0
2 years ago
A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet
gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

h(x)=10+0.1(x^{1.5})

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}

s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx

s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx

s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx

Let 1+0.0225x=t

dx=\frac{1}{0.0225}dt

s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt

s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}

s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}

s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)

s=28.21

Weight of cable=28.21\times 10.4=293.38pound

8 0
3 years ago
Two experiments are defined below. An event is defined for each of the experiments. Experiment I: Corrine rolls a standard six-s
-BARSIC- [3]

Answer: The correct answer is option C: Both events are equally likely to occur

Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;

P(>3) = Number of required outcomes/Number of possible outcomes

P(>3) = 3/6

P(>3) = 1/2 or 0.5

Therefore the probability of rolling a number greater than three is 0.5 or 50%.

For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;

P(Head) = Number of required outcomes/Number of all possible outcomes

P(Head) = 1/2

P(Head) = 0.5

Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on  a tail is equally 0.5 or 50%)

From these results we can conclude that in both experiments , both events are equally likely to occur.

3 0
3 years ago
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