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xxMikexx [17]
3 years ago
7

Draw all constitutional isomers with the molecular formula c4h9br, and then arrange them in order of: increasing reactivity towa

rd an e2 reaction
Chemistry
1 answer:
Anarel [89]3 years ago
5 0
The isomers are: 
CH3CH2CH2CH2-Br most responsive, recause there is slightest gathering around the essential carbon iota for the nucleophile to assault. 
(CH3)2CHCH2-Br second generally responsive. 
.......Br 
.......| 
CH3CHCH2CH3 thid generally responsive. 
(CH3)3C-Br slightest receptive. It is, be that as it may, energetically responsive in a Sn1 response. This is on the grounds that (CH3)3C+ is an exceptionally stable carbonium particle.
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An iceberg has a volume of 9470 ft3.What is the mass in kilograms of the iceberg? The density of ice in the iceberg is 0.92 g/cm
Gemiola [76]
To determine the mass of the iceberg, we simply multiply the density with the volume. Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. Remember that the units should be homogeneous. We calculate as follows:

mass = density x volume
mass = 0.92 g /cm^3 ( 9470 ft^3) ( 30.48 cm / 1 ft )^3 ( 1 kg / 1000 g ) = 265.55 kg
6 0
4 years ago
A chemical reaction with an initial quantity of 1.35 moles of gas is performed in a 4.50-L flask at 24.7°C and under 1.07 atm of
nexus9112 [7]

Answer:

0.488 mol

Explanation:

By the ideal gas law:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.082 atm.L/mol.K), and T is the temperature in K. Thus, after the reaction:

P = 2.92 atm

V = 4.50 L

T = 55.2°C + 273 = 328.2 K

PV = nRT

n = PV/RT

n = (2.92*4.50)/(0.082*328.2)

n = 0.488 mol

8 0
3 years ago
What is the temperature of a 6.1 mole sample of He gas at 18.5 bar and volume of 115L? (Round answer to the hundredths place)
Bond [772]

Answer:

4202.1 K

Explanation:

From;

PV=nRT

P= pressure of the gas = 18.5 bar

V = volume of the gas = 115L

n= number of moles of the gas =  6.1 mole

T= temperature of the gas = ?

R = gas constant = 0.083 L⋅bar⋅K−1⋅mol−1

T = PV/nR

T = 18.5 * 115/6.1 * 0.083

T = 2127.5/0.5063

T= 4202.1 K

7 0
3 years ago
When 45 g of an alloy, at 25°C, are dropped into 100.0g of water, the alloy absorbs 956J of heat. If the temperature of the allo
Novosadov [1.4K]

You can use this formula to help:

c =  \frac{q}{m \:  \times  \: change \: in \: t}

Where:

C = specific heat

q = heat

m = mass

t = temperature

What we know:

C = unknown

q = 956 J

m = 45 g

change in t = 12°C because 37°C - 25°C = 12°C

Plug known values into the formula:

C = 956 J / (45 g) (12°C) and we are left with a specific heat of 1.77J/g°C

Now, convert Joules to calories and then you get:

Answer: A. 0.423 cal/g°C

7 0
3 years ago
Read 2 more answers
The chemical equation below shows the reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O)
Leona [35]
The answer you have marked is correct
6 0
3 years ago
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