Answer:
(A) 4.616 * 10⁻⁶ M
(B) 0.576 mg CuSO₄·5H₂O
Explanation:
- The molar weight of CuSO₄·5H₂O is:
63.55 + 32 + 16*4 + 5*(2+16) = 249.55 g/mol
- The molarity of the first solution is:
(0.096 gCuSO₄·5H₂O ÷ 249.55 g/mol) / (0.5 L) = 3.847 * 10⁻⁴ M
The molarity of CuSO₄·5H₂O is the same as the molarity of just CuSO₄.
- Now we use the dilution factor in order to calculate the molarity in the second solution:
(A) 3.847 * 10⁻⁴ M * 6mL/500mL = 4.616 * 10⁻⁶ M
To answer (B), we can calculate the moles of CuSO₄·5H₂O contained in 500 mL of a solution with a concentration of 4.616 * 10⁻⁶ M:
- 4.616 * 10⁻⁶ M * 500 mL = 2.308 * 10⁻³ mmol CuSO₄·5H₂O
- 2.308 * 10⁻³ mmol CuSO₄·5H₂O * 249.55 mg/mmol = 0.576 mg CuSO₄·5H₂O
Answer:
CO₃²⁻ + Zn²⁺ → ZnCO₃(s)
Explanation:
The net ionic equation is defined as a chemical equation for a reaction that lists only those species participating in the reaction.
In the reaction of sodium carbonate (Na₂CO₃) with zinc iodide (ZnI₂) that produce solid zinc carbonate (ZnCO₃) and a solution of sodium iodide (NaI) the formula is:
2Na⁺ + CO₃²⁻ + Zn²⁺ + 2I⁻ → ZnCO₃(s) + 2Na⁺ + 2I⁻
The net ionic equation is:
<em> CO₃²⁻ + Zn²⁺ → ZnCO₃(s)</em>
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I hope it helps!
Answer: B. Magnification.
Yes you are absolutely right. Although Enlargement and Magnification have similar meanings, the correct term used for objects that get larger in a microscope is called magnification. Magnification in a microscope refers to the enlargement of the object that is being observed in the microscope.
63.546 miles of copper,Cu,are in 19.2g of copper
Gas to solid ( a ) is correct i think