The distance between city A and city B is 22 miles. The distance between city B and city C is 54 miles. The distance between cit
y A and city C is 51 miles. What type of triangle is created by the three cities?
an acute triangle, because 222 + 542 >512
an acute triangle, because 222 + 512 >542
an obtuse triangle, because 222 + 542 >512
an obtuse triangle, because 222 + 512 >542
54 is the hypotenuse because it is the longest side. Square all of the sides. So 54^2=2916 51^2=2601 22^2=484 Now you have 2916=2601+484 Add the two and they will be greater than 2916. Because of that, you will have an acute triangle because 22^2+51^2>54^2 In short, its B
<span>The answer is an acute triangle, because 22^2 + 51^2 > 54^2. In order to find out whether a triangle is acute or obtuse, we must square the lengths of all sides of the triangle. If the largest side's square is less than the two smallest sides' squares added together, than you have an acute triangle. If the largest side's square is larger though, than you have an obtuse triangle.</span>
A) the angle is 105 because its supplemental with the 75 degree angle B) the angle's 75 because the given 75 degree angle is correspondant C) 105 again because they are supplemental
