The area of the two triangular bases is
(total base area) = 2×(1/2)bh
= bh
= (10 m)(6 m) = 10·6 m² = 60 m²
The area of the three rectangles making up the remaining faces of the prism is
(total lateral area) = length×base + length×height + length×hypotenuse
= length×(base + height + hypotenuse)
= (16 m)(10 m + 6 m + 11.6 m)
= (16 m)(27.6 m) = 16·27.6 m² = 441.6 m²
Then the surface area of the prism is the sum of these
surface area = total base area + total lateral area
= 60 m² + 441.6² = 501.6 m²
When rounded to the nearest whole number, this is
A) 502 m²
Answer:
27
Step-by-step explanation:
A = pi * r^2
radius 14 ft
A = 3.14 * 14^2
A = 3.14 * 196
A = 615.44...rounds to 615
radius 10 ft
A = 3.14 * 10^2
A = 3.14 * 100
A = 314
difference is : 615 - 314 = 301...I guess it is C...because of the rounding
