Question

An electron is accelerated by a potential difference of 50v, what is the de broglie wavelength?

Answer 1

Answer:

$1.73553\times 10^{-10}\ m$

Explanation:

h = Planck's constant = $6.626\times 10^{-34}\ m^2kg/s$

K = Potential difference = 50 V

m = Mass of electron = $9.11\times 10^{-31}\ kg$

The de broglie wavelength is given by

$\lambda=\dfrac{h}{\sqrt{2mK}}\\\Rightarrow \lambda=\dfrac{6.626\times 10^{-34}}{\sqrt{2\times 9.11\times 10^{-31}\times 50\times 1.6\times 10^{-19}}}\\\Rightarrow \lambda=1.73553\times 10^{-10}\ m$

The wavelength is $1.73553\times 10^{-10}\ m$