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mixas84 [53]
4 years ago
12

Help please, Mathematics!

Mathematics
2 answers:
kirill115 [55]4 years ago
5 0

Answer:

B. 3,300

Divide 28,875 by 109,800,724.

mario62 [17]4 years ago
5 0

Answer:

B

Step-by-step explanation: I divide 109,800,724 and 28,875. I used calculator and estimated

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Given the triangles below, determine if they are similar. *
natta225 [31]

Answer44

Step-by-step explanation:

5+5=10

6 0
3 years ago
Write the equation in slope intercept form with a slope of -3 and passes through (1,4)
vichka [17]
Y = mx + b, where m = slope, and b = y-intercept.

Since you are not given the y-intercept, you have to solve for it through the equation, y = -3x (which is the slope you are given) + b, and replace x and y with values given, which are (1,4)

y = -3x + b
4 = -3(1) + b
4 = -3 + b
7 = b

Then replace b in the first equation to get the answer
y = -3x + 7
3 0
3 years ago
Is the following sentence a statement or not a statement? X and Y define a line
spayn [35]
Statement because it's stating that x and y define a line.
5 0
3 years ago
Between which two integers does -13/3 lie?
Tcecarenko [31]

Answer:

-4 and -5

Step-by-step explanation:

- 13/3 is equal to -4.3 so this is why i think this but it maybe wrong.

5 0
4 years ago
4.Is it sometimes, always, or never true that, if A and B both have dimensions n x n , AB=BA ? Explain.
REY [17]

Answer: Is true sometimes.

Step-by-step explanation:

I guess that here we have two matrices, A and B, that are nxn.

We can see that if those matrices can conmutate, then we can try it with some simple matrices.

A = \left[\begin{array}{ccc}1&0\\0&-1\end{array}\right] . B =  \left[\begin{array}{ccc}2&0\\1&1\end{array}\right]

Here, we would have that:

AB =  \left[\begin{array}{ccc}2&0\\-1&-1\end{array}\right]

BA =  \left[\begin{array}{ccc}2&0\\1&-1\end{array}\right]

You can see that AB and BA are different, then the statement is not always true.

But it is true sometimes, if A or B are the identiti, then I*A = A*I, in this case would be true.

It is also true if A and B are diagonal matrices, let's prove it:

A =  \left[\begin{array}{ccc}a&0\\0&b\end{array}\right] , B =  \left[\begin{array}{ccc}c&0\\0&d\end{array}\right]

AB =  \left[\begin{array}{ccc}ac&0\\0&bd\end{array}\right] = BA

5 0
4 years ago
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