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3 years ago

The bar graph shows the number of school days Jalen had homework and did not have homework during the first six months of

Mathematics

1 answer:

Oksanka [162]3 years ago

4 0

Given:

In July:

Number of days he has done the homework = 6

Number of days he has not done the homework = 4

In August:

Number of days he has done the homework = 16

Number of days he has not done the homework = 7

In September:

Number of days he has done the homework = 14

Number of days he has not done the homework = 4

In October:

Number of days he has done the homework = 14

Number of days he has not done the homework = 8

In November:

Number of days he has done the homework = 16

Number of days he has not done the homework = 4

In December:

Number of days he has done the homework = 5

Number of days he has not done the homework = 10

To find the months in which the difference between the number of days with homework and with no homework greater than 6.

Now,

In July,

The difference between the number of days with homework and with no homework = 6-4 = 2

In August,

The difference between the number of days with homework and with no homework = 16-7 = 9

In September,

The difference between the number of days with homework and with no homework = 14-4 = 10

In October,

The difference between the number of days with homework and with no homework = 14-8 = 6

In November,

The difference between the number of days with homework and with no homework = 16-4 = 12

In December,

The difference between the number of days with homework and with no homework = 10-5 = 5

Hence,

In 3 months the difference between the number of days with homework and with no homework greater than 6 and these are: August, September, November.

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3 years ago

Read 2 more answers

Miguel quiere entrenar para la carrera solidaria de verano en uno de los dos parques que tiene cerca de casa. Su plan es correr

kondor19780726 [428]

Answer:

The square park is more convenient.

Explanation:

The translation of the question is:

Miguel wants to train for the summer solidarity race in one of the two parks that he has close to home. His plan is to run about 10 km each day and he wants to do an exact number of laps around the park to always start and end at the entrance. Since he has not quite decided between the square and the rectangular park, he decides to do some calculations to see which one suits him best.

Square park: 423 meters each side

Rectangular park: 673 meters measures the base and 218 meters the height

<h2>Solution</h2>

1. Calculate the perimeter of the square park

The perimeter of a square is the sum of the four side lengths. Since they are equal it is:

Perimeter = 4 × side lenght

Perimeter = 4× 423m = 1,692 m

2. Calculate how many times 1,692m is in 10 km

10 km is 10,000 m. Then, divide 10,000 by 1,692 m:

Number of laps = 10,000m / 1,692m ≈ 5.91 laps

3. Calculate the perimeter of the rectangular park

Perimeter = 2×base + 2×height

Perimeter = 2×673m + 2×218m = 1,782m

4. Calculate how many times 1,782 is in 10km

Number of laps = 10,000m / 1,782m ≈ 5.61 laps

Then, since the number 5.91 is closer to an integer number than 5.61, you conclude that the square park is more conventient, because by running 6 laps around the square park the number of kilometers run will be closer to 10 km than with any number of complete laps in the rectangular park.

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3 years ago

Two methods are used to predict how many customers will call in for help in the next four days. The first method predicts the nu

Maru [420]

Answer:

The Second Method

Step-by-step explanation:

APE (Absolute Percentage Error) = absolute difference / actual * 100

APE for First method = 61.93

APE for second method = 54.97

MAPE (Mean absolute Percentage error) = Sum of absolute Percentage error/ Number of observations. ( i.e., 4)

Then,

MAPE for the first method = 61.93 / 4 = 15.482

MAPE for the second method = 54.97 / 4 = 13.472

So, MAPE for second method is less than the MAPE for first method.

8 0

3 years ago

Alexus [3.1K]

Answer:

1. 10mn - 35 2. 8rs -2r + 16

Step-by-step explanation:

10mn - 35

8rs -2r + 16

3 0

3 years ago

1.Do you think a similar rule is true for cosine? That is, does –cos(θ) = cos(–θ)? Pick a value of θ and test this theory.

adell [148]

1.Do you think a similar rule is true for cosine? That is, does -cos (θ) = cos (-θ)? Pick a value of θ and test this theory.

It is not the same.
To prove it, let's choose a value of the angle:
θ = 45 degrees:
-cos (θ) = cos (-θ)
-cos (45) = cos (-45)
- (root (2) / 2) = (root (2) / 2)
answer:
NOT fulfilled: -cos (θ) = cos (-θ) (false)

2. Using your example above, speculate on a rule that might be true for cos (-θ).
cos (θ) = cos (-θ)
To prove it, let's choose a value of the angle:
θ = 45 degrees:
cos (θ) = cos (-θ)
cos (45) = cos (-45)
(root (2) / 2) = (root (2) / 2)
answer
A rule for cosine can be:
cos (θ) = cos (-θ)

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3 years ago