The maximum value of the objective function is 31.787
<h3>How to maximize the function?</h3>
The given parameters are:
Objective function:
Max P = 4x + 5y + 21
Subject to:
y- x < 1
21x + 7y < 25
x>-2, y>-4
Rewrite the inequalities as equation
y - x = 1
21x + 7y = 25
Add x to both sides in y - x = 1
y = x + 1
Substitute y = x + 1 in 21x + 7y = 25
21x + 7x + 7 = 25
Evaluate the like terms
28x = 18
Divide both sides by 28
x = 0.643
Substitute x = 0.643 in y = x + 1
y = 0.643 + 1
y = 1.643
So, we have:
Max P = 4x + 5y + 21
This gives
P = 4 * 0.643 + 5* 1.643 + 21
Evaluate
P = 31.787
Hence, the maximum value of the objective function is 31.787
Read more about maximum functions at:
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False, I don't think it makes any sense.
Hello! I believe the answer to your question is C (hours). If t is the amount of time it takes, hours is a unit of time, therefore I assume that would be your answer. :)
Answer:
Step-by-step explanation:
Equation of line k is y = (-4/7)x + 1
point (-5,-10); m = -4/7
Line L is perpendicular to k so the perpendicular slope will be 7/4
Equation of line L is (y - y1) = m(x-x1)
y+10 = (7/4) (x +5)
4y + 40 = 7x + 35
4y = 7x - 5
y = (7/4)x - (5/4)
