Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
The value decimal point is changing going to the right as you divide a number by 10.
For example
=> 2000.3 / 10
notice the decimal point
=> 200.013, the value of decimal numbers increases as the value of whole number decreases.Let’s divide again
=> 200.013 / 10
=> 20.0013 , now we already have 4 digits in our decimals.
So, simply as we divide the given number by 10, the decimal point moves to the left making the value of whole number decreases and making the number of digits of decimal increase.
I need a photo to tell you the answer
If you choose 10 swimmers and 4 are Stingrays, you can say that Stingrays make up roughly 40% of the swimmers. If 20 Stingrays make up 40% of all the swimmers, we just have to find what number 20 is 40% of. That’s easy enough by cross multiplication:
20/x = 40/100
20/x = 4/10
20/x = 2/5
x = 50.
Double check by multiplying 50 * 0.4. Since 50 * 0.4 = 20, we know we have the right answer. There are about 50 swimmers on this team.
Step-by-step explanation:
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