Answer:
100 yds^2
Step-by-step explanation:
To find the area of a square, we need to know the length of one side of the square. Since the perimeter is 4 times the length of one side, or 4s, and since 4s = 40 yds, s must be 10 yds.
Then the area of the square is (10 yds)^2 = 100 yds^2.
When we say right triangle, it is a triangle that has at least one angle equal to 90 degrees. In addition, an isosceles triangle can also be considered a right triangle given that it has two sides that are equal. In the given measurements above, the set is not considered as measurements of a right triangle. Therefore, the answer is FALSE. Hope this answer helps.
Given:
A right prism has height 7½ and triangular bases with sides of length 5, 12, and 13.
To find:
The total surface area of the prism.
Solution:
We have,
Height of prism = 7½ = 7.5
Sides of triangular base are 5, 12, 13. These sides of Pythagorean triplets because



So, the base of the prism is a right triangle.
Area of a triangle is



The area of the base is equal to the area of the top, i.e.,
sq units.
Perimeter of the base is


The curved surface area of the prism is



Now, the total area of the prism is



Therefore, the total surface area of the triangular prism is 285 square units.
Answer:
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Step-by-step explanation:
Previous concepts
The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

Solution to the problem
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
57.4/10=5.74
the answer is 5.74