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Stolb23 [73]
3 years ago
11

Let F(x)= 5x-4 And G(x)=x+7 Find f(g(x))

Mathematics
1 answer:
irina [24]3 years ago
6 0

Answer:

5x+31

Step-by-step explanation:

f(g(x))

5(x+7) -4

5x+35-4

5x+31=f(g(x))

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Find the value of c. 16 = 4 - 3c
dybincka [34]

Answer:

c = -4

Step-by-step explanation:

16 = 4 - 3c

subtract 4 from each side

16-4 = 4-4 - 3c

12 = -3c

Divide each side by -3

12/-3 = -3c/-3

-4 =c

6 0
3 years ago
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A math test is worth 100 points and has 38 problems. Each problem is worth either 5 points or 2 points. How many problems of eac
Nat2105 [25]

Answer:

<em><u>5</u></em><em><u> </u></em><em><u>points</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>8</u></em>

<em><u>and</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>po</u></em><em><u>ints</u></em><em><u> questions</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

Step-by-step explanation:

Let the number of 5 points questions be x and number of the 2 points questions be y !!

Given :- The paper has 38 problems

i.e,

number of 5 points Q + number of 2point Q = 38

=> x + y = 38

=> x = 38 - y .... ( i )

And , The test worth 100 pts :-

There must be x number of Questions which carry 5 points and there must y number of questions which carries 2 points ( as assume above )

so, 5x + 2y = 100 .... ( ii )

Putting value of the x in ( ii )

5 ( 38 - y ) + 2y = 100

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Putting value of y in ( i )

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So, the Number of 5points Question is

x = 8

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4 0
3 years ago
Which ordered pairs could be used to graph the equation 2x+y=5
Marrrta [24]

Answer:

(-2,9) ,(4,-3)

Step-by-step explanation:

Given the expression 2x+y=5

We are required to look for values of x and y such that when substituted into the given expression will result in the number 5

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Let us plug in the values to check

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2. (4,-3)

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