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2 years ago

Let F(x)= 5x-4 And G(x)=x+7 Find f(g(x))

Mathematics

1 answer:

irina [24]2 years ago

6 0

Answer:

5x+31

Step-by-step explanation:

f(g(x))

5(x+7) -4

5x+35-4

5x+31=f(g(x))

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Rewrite this inequality so y is by itself:<br><br> 3x − 4y ≥ 24.

vazorg [7]

Answer:

y $\leq$ 6 + $\frac{3x}{4}$

Step-by-step explanation:

3x - 4y $\geq$ 24

-3x -3x

(-4y $\geq$ 24 - 3x ) / -4

y $\leq$ 6 + $\frac{3x}{4}$

8 0

2 years ago

Morgan is walking her dog on an 8-meter-long leash. She is currently 500 meters from her house, so the maximum and minimum dista

lara31 [8.8K]

<u>The minimum distance is 492 meters from the house (500 - 8 = 492), and the maximum distance is 508 meters from the house (500 + 8 = 508). The dog may be slightly closer to the house, depending on how long the dog is, or if Morgan is using a leash extender.</u>

3 0

3 years ago

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Whats the midline equation ?

PSYCHO15rus [73]

Answer:

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Step-by-step explanation:

8 0

2 years ago

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Use the quadratic formula to find the solutions to the equation x^2-3x+1=0

Gnom [1K]

Answer:

$x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}$

Step-by-step explanation:

Using:

$x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}$

we will have two solutions.

x^2-3x+1=0

So, a=1 b=-3 c=1

$x_{1}=\frac{+3+\sqrt{-3^{2}-4*1*1} }{2*1}\\\\x_{2}=\frac{+3-\sqrt{-3^{2}-4*1*1} }{2*1}$

We have two solutions:

$x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}$

4 0

3 years ago

Which expressions are equivalent to when x0? Check all that apply.

Genrish500 [490]

We have that

$\frac{(x+4)}{3} / \frac{6}{x} = \frac{x*(x+4)}{3*6} \\ \\ = \frac{( x^{2} +4x)}{18}$

therefore

case a)
$\frac{(x+4)}{3} * \frac{x}{6}$
Is equivalent

case b)
$\frac{6}{x} * \frac{(x+4)}{3}$
Is not equivalent

case c)
$\frac{x}{6} * \frac{(x+4)}{3}$
Is equivalent

case d)
$\frac{(2 x^{2} +4x)}{6}$
Is not equivalent

case e)
$\frac{(2 x^{2} +4x)}{18}$
Is equivalent

Hence

the answer is

$\frac{(x+4)}{3} * \frac{x}{6}$

$\frac{x}{6} * \frac{(x+4)}{3}$

$\frac{(2 x^{2} +4x)}{18}$

3 0

2 years ago

Read 2 more answers